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Anettt [7]
2 years ago
5

Had to repost it for a better look if still cant see it txt me at 3343729907

Mathematics
1 answer:
kompoz [17]2 years ago
4 0

Answer:

still cant see it sjwjejie

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So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.

f(x)=\sin(\omega(x))\\\\f(\pi^n)=\sin(\omega(\pi^n))=0, n\in\mathbb{N}\\\\\\\sin x=0 \implies x=k\pi,k\in\mathbb{Z}\\\Downarrow\\\omega(\pi^n)=k\pi\\\\\boxed{\omega(x)=k\sqrt[\log_{\pi} x]{x},k\in\mathbb{Z}}

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\large V=a^3 \\ \\V_{1}=(6a)^3 =6^3*a^3=256a^3\\ \\\frac{V_{1}}{V}=\frac{256 \not a^3^1}{\not a^3^1}= 256\\ \\Answer : \ increase \ the \ volume \ of \ a \ cube \ 256 \ times


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