Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer:
false: positive and negative numbers are on two completely opposite sides of a number line, coordinate plane, etc. Just like 4 is different than 5, it is the same with positive and negative numbers
Answer:
I believe that it would be 10^3. (10x10x10)
Sorry if I'm wrong I'm just a little confused with the question you asked :/
22 + (30 - 4) divided by 2
30 - 4 = 26
26/2 = 13
22 + 13 = 35
35
18 + (22 - 4) divided by 6
22 - 4 = 18
18 divided by 6 = 3
18 + 3 = 21
21
Well, if the radius is 10, then the circumference is
What's the unit? Either way, 22 rev. per minute means each minute you go by
units per second. Now you got the linear speed, just find out the time by dividing the distance by the speed!
So, what's the unit for the radius?
