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Ket [755]
3 years ago
8

17. The ff. are true of ligands

Biology
1 answer:
Anestetic [448]3 years ago
5 0
The answer is clearly B
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A couple without an ancestral history of Tay-Sachs disease (a rare autosomal recessive) have two normal children and an infant a
Bas_tet [7]

Answer:

The probability is 25%.

Explanation:

  • Let the dominant allele for the disease be 'T' and recessive allele be 't'.
  • The couple with normal phenotype produces an infant with the Tay Sach's disease.
  • As the disease is autosomal recessive in nature, it will get expressed in a homozygous recessive condition, that is, when the genotype is : tt.
  • As the normal parents are producing a diseased offspring, the both parents must be heterozygous dominant (Tt) for the disease allele.
  • The brother of the husband and the sister of the wife, both having a normal phenotype, can have the following genotypes, TT or Tt.
  • If either of the individual (brother or sister) has TT genotype and the other has other has either TT or Tt genotype, there is zero probability that they will produce an offspring with the disease.

                     T          T                        and                       T            T

             T     TT        TT                                             T     TT         TT

                     (N)        (N)                                                    (N)        (N)

             T      TT        TT                                             t      Tt          Tt        

                     (N)        (N)                                                    (N)         (N)

  • If both the individuals have a Tt genotype, the probability to produce  diseased offspring is one-fourth or 25%.

                                               T             t

                                   T        TT           Tt

                                             (N)           (N)

                                    t        Tt             tt

                                             (N)           (D)

  • (N) stands for normal and (D) stands for diseased phenotype.

           

7 0
4 years ago
The map shows the distribution of wild boars in the United States. Wild boars are an invasive species to the United States.
elena55 [62]

Answer:  down there

Explanation: Feral swine are not native to the Americas. They were first brought to the United States in the 1500s by early explorers and settlers as a source of food. Free-range livestock management practices and escapes from enclosures led to the first establishment of feral swine populations within the United States. In the 1900s, the Eurasian or Russian wild boar was introduced into parts of the United States for the purpose of sport hunting. Today, feral swine are a combination of escaped domestic pigs, Eurasian wild boars, and hybrids of the two.

Feral swine have been reported in at least 35 states. Their population is estimated at over 6 million and is rapidly expanding. Range expansion over the last few decades is due to a variety of factors including their adaptability to a variety of climates and conditions, translocation by humans, and a lack of natural predators.

7 0
3 years ago
Read 2 more answers
Greg has been given a small sample of metal. His teacher has assigned him to identify what type of metal he was given.
lyudmila [28]
A ability to rust bc it just it
7 0
3 years ago
Which base does RNA have that DNA does not have?
Dmitrij [34]

Answer:

Uracil "U"

Explanation:

RNA shares Adenine (‘A’), Guanine (‘G’) and Cytosine (‘C’) with DNA, but contains Uracil (‘U’) rather than Thymine.

4 0
3 years ago
Small structures inside cells that perform specific functions are called:
frosja888 [35]

Answer:

B. Organelles

Explanation:

they are called

6 0
3 years ago
Read 2 more answers
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