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HACTEHA [7]
3 years ago
10

H e e e e l l l ppppp

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
the answer is c lol
astra-53 [7]3 years ago
4 0

Answer: C

Step-by-step explanation:

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A gift is a cube with a volume of 512 cubic inches. What is the length of each edge of the box?
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The volume of a box is the length x with x height. Because it is a cube all the sides are the same size, and it’s has three dimensions. That means you can calculate the length of one side by picking the root^3 (I don’t know what it is in English it is a square root with a 3 in the upper left corner) of 512. That gives you 8, so the sides are 8 inches Kong’s
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3 years ago
June paid 4.50 in tax on jeans and a sweatshirt that cost a total of 60.00. What percent tax did she pay?
MAXImum [283]
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6 0
3 years ago
6x + 3y = 12<br> 4x + y = 14 what is the solution
weeeeeb [17]

Answer:

x=5 y=-6

Step-by-step explanation:

6x + 3y = 12  , 4x + y = 14

4x*3+y*3=14*3

12x+3y=42 , 6x+3y=12

(12x-6x)+(3y-3y)=30

6x=30, x=5

4*5 + y = 14

y=-6

8 0
3 years ago
What is the length of the hypotenuse?
Charra [1.4K]

Answer:

Hello! answer: 85

Step-by-step explanation:

68 × 68 = 4624

51 × 51 = 2601

4624 + 2601 = 7225

√7225 = 85

85 × 85 = 7225 therefore c = 85 Hope that helps!

7 0
3 years ago
Read 2 more answers
You are given the following sequence:
borishaifa [10]
<h2>                     Question No 1</h2>

Answer:

7.5 is the 4th term of the sequence 60, 30, 15, 7.5, ... .

In other words:   \boxed{a_4=7.5}

Step-by-step explanation:

Considering the sequence

60, 30, 15, 7.5, ...

As we know that a sequence is said to be a list of numbers or objects in a special order.

so

60, 30, 15, 7.5, ...  

is a sequence starting at 60 and decreasing by half each time. Here, 60 is the first term, 30 is the second term, 15 is the 3rd term and 7.5 is the fourth term.

In other words,

a_1=60,

\:a_2=30,

a_3=15, and

a_4=7.5

Therefore, 7.5 is the 4th term of the sequence 60, 30, 15, 7.5, ... .

In other words:   \boxed{a_4=7.5}

<h2>                       Question # 2</h2>

Answer:

The value of a subscript 5 is 16.

i.e. When n = 5, then h(5) = 16

Step-by-step explanation:

To determine:

What is the value of a subscript 5?

Information fetching and Solution Steps:

  • Chart with two rows.
  • The first row is labeled n.
  • The second row is labeled h of n. i.e. h(n)
  • The first row contains the numbers three, four, five, and six.
  • The second row contains the numbers four, nine, sixteen, and twenty-five.

Making the data chart

n                  3         4         5         6

h(n)               4         9         16       25

As we can reference a specific term in the sequence by using the subscript. From the table, it is clear that 'n' row represents the input and and 'h(n)' represents the output.

So, when n = 5, the value of subscript 5 corresponds with 16. In other words: When n = 5, then h(5) = 16

Therefore, the value of a subscript 5 is 16.

<h2>                         Question # 3</h2>

Answer:

We determine that the sequence 33, 31, 28, 24, 19, … is neither arithmetic nor geometric.

Step-by-step explanation:

Considering the sequence

33, 31, 28, 24, 19, …

Lets calculate the common difference 'd' to determine if the sequence is Arithmetic or not.

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

d = 31 - 33 = -2

d = 28 - 31 = -3

d = 24 - 28 = -4

d = 19 - 24 = -5

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

Lets now calculate the common ratio 'r' to determine if the sequence is Geometric or not.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}

\frac{31}{33}=0.93939\dots ,\:\quad \frac{28}{31}=0.90322\dots ,\:\quad \frac{24}{28}=0.85714\dots ,\:\quad \frac{19}{24}=0.79166\dots

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence 33, 31, 28, 24, 19, … is neither arithmetic nor geometric.

<h2>                         Question # 4</h2>

Answer:

We determine that the sequence -99, -96, -92, -87, -81... is neither arithmetic nor geometric.

Step-by-step explanation:

From the description statement:

''negative 99 comma negative 96 comma negative 92 comma negative 87 comma negative 81 comma dot dot dot''.

The statement can be translated algebraically as

-99, -96, -92, -87, -81...

Lets calculate the common difference 'd' to determine if the sequence is Arithmetic or not.

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-96-\left(-99\right)=3,\:\quad \:-92-\left(-96\right)=4,\:\quad \:-87-\left(-92\right)=5,\:\quad \:-81-\left(-87\right)=6

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

Lets now calculate the common ratio 'r' to determine if the sequence is Geometric or not.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}

\frac{-96}{-99}=0.96969\dots ,\:\quad \frac{-92}{-96}=0.95833\dots ,\:\quad \frac{-87}{-92}=0.94565\dots ,\:\quad \frac{-81}{-87}=0.93103\dots

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence -99, -96, -92, -87, -81... is neither arithmetic nor geometric.    

<h2>                      Question # 5</h2>

Step-by-step explanation:

Considering the sequence

12, 22, 30, 36, 41, …

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

22-12=10,\:\quad \:30-22=8,\:\quad \:36-30=6,\:\quad \:41-36=5

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}

\frac{22}{12}=1.83333\dots ,\:\quad \frac{30}{22}=1.36363\dots ,\:\quad \frac{36}{30}=1.2,\:\quad \frac{41}{36}=1.13888\dots

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence 12, 22, 30, 36, 41, … is neither arithmetic nor geometric.                  

8 0
3 years ago
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