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Vera_Pavlovna [14]
3 years ago
5

A teacher has 100 chairs to arrange for an assembly into equal rows Write one way the chairs could be arranged Include the numbe

r of rows and the number of chairs in each row '

Mathematics
2 answers:
VMariaS [17]3 years ago
4 0
<h3><u>Answer:</u></h3>

10 rows with 10 chairs in each row is the best way to arrange 100 chairs to arrange for an assembly into equal rows.

<h3><u>Step-by-step explanation:</u></h3>

A teacher has 100 chairs to arrange for an assembly into equal rows.

That is we have to find an array such that the chairs are equally distributed.

If we arrange 10 chairs in each row and form 10 such rows than the total of  100 chairs could be arranged.

Since 10×10=100.

Hence, from this arrangement we get that:

Number of rows=10

and number of chairs in each row=10

tiny-mole [99]3 years ago
3 0
That's easy if there is 100 chairs there would be 10 rows with ten chairs in each row
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Marrrta [24]

Answer:

c=3

Step-by-step explanation:

8=-5(-1)^2-10(-1)+c

8=5+c

c=3

4 0
3 years ago
-7w+8 (w+1)=w-7<br> Please show work
kvv77 [185]
Hello there.^••^

−7w+8(w+1)=w−7
w+8=w−7
w+8−w=w−7−w8=−7
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6 0
3 years ago
Read 2 more answers
For which function does f decrease by 15% every time x increases by 1
LenaWriter [7]

Answer:

f(x) = 0.85^{x}

Step-by-step explanation:

The exponential function that decrease by 15% every time x increases by 1 is given by:

f(x) =  {(1 - 0.15)}^{x}

We simplify the parenthesis to get:

f(x) = 0.85^{x}

Therefore the decrease by 15% every time x increases by 1 is

f(x) =  {0.85}^{x}

The second choice is correct.

7 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
HELP ASAP Use the data below
beks73 [17]

Answer:

Part A:

   -Minimum: 10

   -Q1: 17.5

   -Median: 30

   -Q3: 42.5

   -Maximum: 50

Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

8 0
4 years ago
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