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2 years ago

10

Dave has 15$ to spend on an 8$ books and two birthday cards (c) for his friends . how much can he spend on each card if he busys

the same card for each other ?

1 answer:

Veronika [31]2 years ago

8 0

15-8 is how much you have left then divide that by 2 and thats ur answer.
$15 - $8 = $7 / 2 = $3.50

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Solve by substitution <br> X^2= 2y + 10<br> 3x-y = 9

Viefleur [7K]

Answer:

$x=-4\\ x=-2\\ y=-21\\ y=-15$

Step-by-step explanation:

$x^{2} =2y+10$

$y=-9+3x$

$x^{2} =2(-9+3x)+10$

$x^{2} =-18+6x+10$

$x^{2} =6x-8$

$x^{2} -6x+8$

$x=-4, -2$

$y=-9+3(-4)$

$y=-9-12$

$y=-21$

$y=-9+3(-2)$

$y=-9-6$

$y=-15$

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mina [271]

-2 + 3b = 5b - 2(2b + 3) Distribute the -2 through the parentheses.
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-2 + 3b = b - 6 Bring all "b's" to one side of the equation
-2 + 3b - b = b - b - 6 Combine like terms
-2 + 2b = -6 Bring the 2 to the right side of the equation
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2 years ago

What’s 20+8(q-11)= -12

MariettaO [177]

20+8q -88= -12
8q -68 = -12
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8q = 56
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3 years ago

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lara [203]

Answer:

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Step-by-step explanation:

Since 20 × 5 =100

Then we do:
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