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Ede4ka [16]
3 years ago
13

ВС Round your answer to the nearest hundredth. B. ? 35° A 2. с

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

a diagram is necessary. please provide a diagram.

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Find the sum of the arithmetic series: 10 + 4 + (-2) + ... + (-50)
Nastasia [14]

<em>Answer</em><em> </em><em>is</em><em> </em><em>-220</em>

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6 0
3 years ago
SOlve the system of equations using substitution<br><br><br> y=2x-10<br> y=4x-8
dezoksy [38]
It should be,
4x-8=2x-10    because you substitute that for y.
Now you do,
4x-2x    because you do the opposite of the positive 2x as you bring it to the other side.
That is,
2x-8=10   now you bring the 8 to the other side.
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3 0
3 years ago
The graph shows the relationship between men's shoe sizes and their heights. What type of relationship is this? a linear relatio
tatiyna

Answer: (A)

a linear relationship showing as height increases, shoes size increases

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Explain how you can write 35% as the sum of two benchmark percents or as a multiple of a percent
OlgaM077 [116]

I'll just take the points thanks XD

3 0
4 years ago
Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1
Nesterboy [21]

Answer:

x=4

Step-by-step explanation:

Given \displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1, start by squaring both sides to work towards isolating x:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2

Recall (a-b)^2=a^2-2ab+b^2 and \sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1

Isolate the radical:

\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}

Square both sides:

\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2

Expand using FOIL and (a+b)^2=a^2+2ab+b^2:

\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36

Move everything to one side to get a quadratic:

\displaystyle-\frac{1}{4}x^2+7x-24=0

Solving using the quadratic formula:

A quadratic in ax^2+bx+c has real solutions \displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}. In \displaystyle-\frac{1}{4}x^2+7x-24, assign values:

\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24

Solving yields:

\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}

Only x=4 works when plugged in the original equation. Therefore, x=24 is extraneous and the only solution is \boxed{x=4}

4 0
2 years ago
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