Answer: 17/18
Step-by-step explanation: You have to find the least common denominator first, since 1/9 and 5/6 have different denominators. The least common denominator is 18. Multiply both the numerator and the denominator of each fraction by the number that makes its denominator equal to the least common denominator.
The equation then becomes 2/18 + 15/18 which equals 17/18 ^-^
Answer:
No. When all you want to do is estimate a population parameter, you should construct a confidence interval.
Step-by-step explanation:
In this case, there is no other prior estimation about the population to test (a hypothesis to nullify). The only thing you can do is construct a confidence interval of the proportion, where the standard deviation can be calculated in function of the proportion and the sample size.
The right answer is E: "No. When all you want to do is estimate a population parameter, you should construct a confidence interval."
Answer: The answer is the first bubble
Step-by-step explanation:
1. When you identify the pairs you get: { ( -5,-4), (-1,5), ( -5,3) , (7,8) }
2. When figuring out whether or not it is a function, you have to see if there are any same y values. If there is no y values that are the same, then the relation is a function.
3. This relation is a function.
* Also, if you have a relation that has the two or more of the same x values, the relation is still a function no matter what.
Area of square base = 324 m²
Length of the square side = √324 = 18
The side of the square is the base of the triangle.
Area of triangle = (1/2)*base* height
135 = (1/2)*18* h
135 = 9h
135/9 = h
15 = h
height = 15 m
To get the height of the Pyramid, the height of the Triangle and half the length of the side of the square form a right angled triangle.
Hypotenus = 15
Half length of square = 18/2 = 9
Height of Pyramid = H
By Pythagoras' Theorem:
15² = H² + 9²
225 =H² + 81
H² + 81 = 225
H² = 225 - 81
H² = 144 Take square root of both sides
H = √144
H = 12
Height = 12 meters.
Option C.
I wrote answers in picture and I use Desmos app to solve this equations
