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Alenkasestr [34]
3 years ago
14

Choose the equation that describes the relationship in the following table. please answer ASAP ty

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Answer:

C) y = -5x + 32

Step-by-step explanation:

Only choice where the all the x values equal the y values

You might be interested in
Write down the answers to a,b,c,d
aniked [119]

Answer:

(A) 1

(B) -2

(C) 3.5

(D) -0.5

Step-by-step explanation:

We can treat each thermometer like a vertical number line and read the values on each.

A is right on 1.

B is right on -2.

C is in the middle of 3 and 4, so 3.5

D is in the middle of 0 and -1, so -0.5

Hope this helped!

3 0
3 years ago
GH bisects CF, CF=2y-2, and CD=3y-11. Find CD and Y
Naily [24]
Since GH bisects CF, therefore:
CD = (1/2) CF
3y - 11 = (1/2) (2y -2)   (multiply both sides by 2)
6y - 22 = 2y - 2
6y - 2y = -2 + 22
4y = 20
y = 5

Substitute with the value of y in the equation of CD, you get:
CD = <span>3y-11 = 3(5) - 11 = 15 - 11 = 4 cm</span>
7 0
3 years ago
Which of the following statements is true?
Hatshy [7]

Answer:

c

Step-by-step explanation:

absolute value of -15 is 15, 15 us more than 10

5 0
3 years ago
1. Which equation can you use to find the value of x?
Alika [10]

Answer:

It's a proportion.

2 is to x as 15 is to 9, or 2/x = 15/9.

Multiply the means and extremes

15x = 18

divide both sides by 15 to get x by itself.

x = 1.2

Step-by-step explanation:

6 0
3 years ago
During an experiment, a ball is dropped from a height of 205 feet. The formula h = -16t2 + h subscript 0 can be used to approxim
guajiro [1.7K]

Answer:

4 seconds

Step-by-step explanation:

h = -16t^2 + h_0

where h=height reached after t seconds

         h_0 = Initial Height of the ball

The ball is dropped from a height of 205 feet,

h_0 = 205 feet

We want to determine the time it takes the ball to reach the ground.

i.e. when height of the ball, h=0

Substituting h_0 = 205 feet and h=0 into the formula

h = -16t^2 + h_0

0 = -16t^2 + 205

Add 16t^2 to both sides

0+16t^2 = -16t^2+16t^2 + 205\\16t^2=205

Divide both sides by 16

\frac{16t^2}{16}= \frac{205}{16}\\t^2=12.8125

t=\sqrt{12.8125} =3.58 ≈ 4 Seconds

It takes approximately 4 seconds for the ball to reach the ground.

7 0
3 years ago
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