The larger of two consecutive ODD numbers is one less than twice the smaller number. Find the larger of the two numbers.
1 answer:
Answer:
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5</h3>
Step-by-step explanation:
z - any integer
2z+1 - any odd integer (the smaller one)
2z+1+2 = 2z+3 - odd integer consecutive to 2z+1 (the larger one)
2(2z+1) - twice the smaller number
2(2z+1) - 1 - one less than twice the smaller number
2(2z+1) - 1 = 2z + 3
4z + 2 - 1 = 2z + 3
2z = 2
z = 1
2z+3 = 2•1+3 = 5
check:
2z+1 = 2•1+1 = 3,
2(2z+1)-1 = 2(2•1+1)-1 = 2•3-1 = 5 = 2z+3
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