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allochka39001 [22]
3 years ago
5

The larger of two consecutive ODD numbers is one less than twice the smaller number. Find the larger of the two numbers.

Mathematics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer:

<h3>             5</h3>

Step-by-step explanation:

z -  any integer

2z+1 - any odd integer (the smaller one)

2z+1+2 = 2z+3 - odd integer consecutive to 2z+1  (the larger one)

2(2z+1)    - twice the smaller number

2(2z+1) - 1    - one less than twice the smaller number

2(2z+1) - 1 = 2z + 3

4z + 2 - 1 = 2z + 3

2z = 2

 z = 1

2z+3 = 2•1+3 = 5

check:

2z+1 = 2•1+1 = 3,  

2(2z+1)-1 = 2(2•1+1)-1 = 2•3-1 = 5 = 2z+3

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4 0
2 years ago
Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.
dusya [7]

\huge\color{black}\underline\mathbb{\:ANSWER}

\green{••••••••••••••••••••••••••••••••••••••••••••••••••}

Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.

x = −5

x = 6

<h2>x = −6</h2>

therefore the answer is

<h2>x = −6</h2>

\green{••••••••••••••••••••••••••••••••••••••••••••••••••}

\tt\color{black}{12:14AM}

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(ノ^_^)ノ

4 0
2 years ago
Read 2 more answers
What is the prduct of 33 and 6925?
liubo4ka [24]

Answer:

228525-Look below for steps:)

Step-by-step explanation:

Step 1:

6925

*   33

______

Step 2:

5*3=15

carry the one

3*2+1=7

9*3=27

carry the 2

6*3+2=20

SO your first number is 20775 but we are NOT done yet!

add a zero below 5

5*3=15

carry the one

3*2+1=7

9*3=27 carry the 2

then 6*3+2=20

then add 207750+20775

which equals....

228525

so 228525 is your answer!!!

<em>I really do hope this made sense!</em>

<em>Have a great day!</em>

<em>- Hailey: D</em>

<em>(NOTHING IS COPIED AND PASTED!!!!!)</em>

3 0
3 years ago
When x2+3x-4 is subtracted from x (x2+3x-2) what is the difference
tankabanditka [31]
I'm assuming this is x^2 + 3x - 4 and x(x^2 + 3x - 2)

1.) First distribute x(x^2 + 3x - 2) to get x^3 + 3x^2 - 2x.

2.) Because you are subtracting all the terms from x^3 + 3x^2 - 2x, it's the same thing as distributing -1 to x^2 + 3x - 4 and then adding it to x^3 + 3x^2 - 2x.

3.) -1(x^2 + 3x - 4) = -x^2 - 3x + 4

4.) Add (x^3 + 3x^2 - 2x) + (-x^2 - 3x + 4)

5.) x^3 + 2x^2 - 5x + 4 is your final answer.

5 0
3 years ago
Read 2 more answers
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