Please answer I will give BRAINLIEST if i can

Mathematics

1 answer:

N76 [4]3 years ago

7 0

Answer:

Glass A holds the most, It holds more than glass B because of its cone shape.

Step-by-step explanation:

I hope I helped you, now have a good day and good luck!! ;)

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rectangle A has a length of 24 meters and a width of 20 meters. rectangle B has the same area as rectangle A. the width of recta

blagie [28]

To solve this, first we'll find the area of the rectangle A,

Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A

now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B

finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m

7 0

3 years ago

Althea paid $5.00 each for two bracelets and later sold each for $15.00. She paid $8.00 each for three bracelets

____ [38]

Answer:

I have the same question

Step-by-step explanation:

message me if anyone helps I need it too

8 0

2 years ago

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$