Answer:
there is no answer they are equal. anything can be put into a and it will still be true
Step-by-step explanation:
4a+8=8+4a
there is no answer
The length is 7 with a width of 5, so the area is 35
Answer: 12.10
Step-by-step explanation:
Given : Mean : ![\mu = 15.45](https://tex.z-dn.net/?f=%5Cmu%20%3D%2015.45)
Standard deviation : ![\sigma = 13.70](https://tex.z-dn.net/?f=%5Csigma%20%3D%2013.70)
The formula to calculate the z-score :-
![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x= 5 degrees
![z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B5-15.45%7D%7B13.70%7D%3D-0.7627737226%5Capprox-0.76)
For x= 10 degrees
![z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B10-15.45%7D%7B13.70%7D%3D-0.397810218%5Capprox-0.40)
The P-value : ![P(-0.76](https://tex.z-dn.net/?f=P%28-0.76%3Cz%3C-0.40%29%3DP%28z%3C-0.40%29-P%28z%3C-0.76%29)
![=0.3445783-0.2236273=0.120951\approx0.1210](https://tex.z-dn.net/?f=%3D0.3445783-0.2236273%3D0.120951%5Capprox0.1210)
In percent , ![0.1210\times100=12.10\%](https://tex.z-dn.net/?f=0.1210%5Ctimes100%3D12.10%5C%25)
Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%
<h3>
Answer: 16 square units</h3>
Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5
a^2 + b^2 = c^2
3^2 + x^2 = 5^2
9 + x^2 = 25
x^2 = 25-9
x^2 = 16
x = sqrt(16)
x = 4
This is a 3-4-5 right triangle.
The height of the parallelogram is 4 units.
We have enough info to find the area of the parallelogram
Area of parallelogram = base*height
Area of parallelogram = 4*4
Area of parallelogram = 16 square units
Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.