The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
check the first two and the last one
Step-by-step explanation:
you use multiplying/dividing and adding/subtraction to get the answer
10x+45x-13 = 11(5x+6)
55x-13 = 11(5x+6) combine like terms
55x-13 = 55x+66 distribute the 11 to the 5x and 6
-13 = 66 cancel out equal terms on both sides
the statement is false meaning there is equation has no solution
Answer:
Step-by-step explanation:
B. Vertically stretch by a factor of 3, and
D. Shift down 1 unit.
Answer is C they are equal.
