Answer:
The worth of one bill is $20 and the worth of the other bill is $1
Step-by-step explanation:
Let
x----> the worth of one bill
y ---> the worth of the other bill
I assume x > y
we know that
x+y=21 ----> equation A
x=y+19 ---> equation B
Solve the system by elimination
Multiply equation B by -1 both sides
-x=-y-19 ----> equation C
Adds equation A and equation C
x+y=21
-x=-y-19
------------
y=21-y-19
2y=2
y=1
Find the value of x
x=y+19 -----> x=1+19=20
therefore
The worth of one bill is $20 and the worth of the other bill is $1
28 x 3 3/4 = 84 + 21 = 105 copies.
Multiply the second equation by -3 in order to cancel out U
3u+z=15
-3(u+2z)=10
3u+z=15
-3u-6z=-30. Then u subtract those two equations
-5z=-15
Z=3
To solve for u, plug in the z in one of the equation (doesn’t matter which one)
3u+3=15
3u=12
U=4
Ur answer is
U=4. Z=3
Answer:
5 and 1/3 cups of soil
Step-by-step explanation:
Hello there, in this problem we can solve for the amount of soil that Katie will need by multiplying the factor for one of them by the number of pots we have, 8. We get 16/3 cups of soil, or 5 and 1/3 cups of soil.
Hope this helps!
-HM
The base will have the greatest area for a given perimeter if it is square. If the edge of the square base has length x (in feet), then the total material requirement in square feet is
.. m = x^2 +(4/x^2)*(4x)
.. m = x^2 +16/x
This will have a minimum where dm/dx = 0.
.. dm/dx = 2x -16/x^2 = 0
.. x^3 = 8 . . . . . . . . . . . . . . . multiply by x^2/2 and add 8
.. x = 2
The tank is 2 feet square and 1 ft high.
_____
You will note that it is half the height of a cube that has double the volume. This is the generic solution to all minimum cost open-top box problems. Actually, the costs of pairs of opposite sides are equal to each other and to the cost of the base. If material costs are not identical in all directions, that is the more generic solution.
