What is the converse of the statement? if p then q

(06.06) 4 3(x + 4) represents the area of the rectangle above. Which expression below is equivalent by the Distributive Property

Alexeev081 [22]

Answer:

im on the same one if i get it right i will comment and tell u k?

Step-by-step explanation:

kk

6 0

2 years ago

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Please help. Is algebra.

Dvinal [7]

Answers:

Blank 1: 4
Blank 2: -1

So the solution is (x,y) = (4, -1)

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Work Shown:

6x + 7y = 17

6x + 7( y ) = 17

6x + 7( -3x+11 ) = 17 ... replace every copy of y with -3x+11

6x - 21x + 77 = 17

-15x = 17-77

-15x = -60

x = -60/(-15)

x = 4

We'll use this x value to find y

y = -3x+11

y = -3(4)+11 ... replace x with 4

y = -12+11

y = -1

We have x = 4 and y = -1 pair up together to give us the solution (x,y) = (4, -1)

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To check the solution, we plug x = 4 and y = -1 into each equation

Plugging the values into the first equation leads to...

y = -3x+11

-1 = -3(4)+11

-1 = -1

This is effectively already done in the last part of the previous section. But it doesn't hurt to verify like this regardless.

We'll need to verify the second equation as well.

6x + 7y = 17

6(4) + 7(-1) = 17

24 - 7 = 17

17 = 17

We get a true equation, so the solution is confirmed with both equations. Overall, the solution to the system of equations is confirmed. This system is independent and consistent.

3 0

3 years ago

A lamp shade has a radius of 9 inches. What is the circumference of the top of the shade? Use 3.14 to approximate pi. Round your

Black_prince [1.1K]

c = circumference pi = 3.14 r = radius = 9 inches d = diameter c=pi*d The radius is half of the diameter, d = 2r. Then d = 2*9=18. plug into equation. c= pi*d = 3.14*18 round accordingly and you may want to include that the measurement you end up with is in inches.

4 0

2 years ago

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Max used 3 7/8 pounds of yellow potatoes and 2 5/8 pounds of sweet potatoes to make a potato salad. How many more pounds of yell

Talja [164]

Answer:

3 7/8-2 5/8

31-21

8

=10/8

=1 1/4 more

5 0

2 years ago

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Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

3 years ago