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3 years ago

The wavelength of a water wave is 6 cm when the frequency is 10 hertz .

Physics

1 answer:

dedylja [7]3 years ago

4 0

The distance between successive crests (or successive troughs) is defined as the wavelength. The time elapsed between the crossings of two successive crests through a given point is the period of the wave.
The Velocity of propagation (Vp) of a cable is the speed at which an electrical signal can propagate through the cable in comparison to the speed of light. For example, in a vacuum, the velocity of propagation would be 100% or 1 (depending on how it is represented).
The wave period is the time it takes to complete one cycle. The standard unit of a wave period is in seconds, and it is inversely proportional to the frequency of a wave, which is the number of cycles of waves that occur in one second.

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A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the building.

Nadusha1986 [10]

The height of the building is 53.4 m (projectile motion)

Explanation:

The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:

$d=v_x t$

where:

$v_x = 50 m/s$ is the horizontal velocity of the ball, which is constant since there are no forces in this direction

d = 165 m is the horizontal distance travelled by the ball

Solving for t, we find the time of flight:

$t=\frac{d}{v_x}=\frac{165}{50}=3.3 s$

Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation

$s=ut+\frac{1}{2}at^2$

where

s is the vertical displacement, which is the height of the building

u = 0 is the initial vertical velocity of the ball

t = 3.3 s is the time of flight

$a=g=9.8 m/s^2$ is the acceleration of gravity

Solving for s, we find the height of the building:

$s=0+\frac{1}{2}(9.8)(3.3)^2=53.4 m$

Learn more about projectile motion here:

brainly.com/question/8751410

#LearnwithBrainly

6 0

4 years ago

What is the weigh in newtons of an automobile with a mass of 1800 kg?

Allushta [10]

Answer:

The weight of an automobile, W = 17640 N

Explanation:

Given that,

The mass of an automobile, m = 1800 Kg

The weight of an object is represented as the gravitational force acting on an object of mass 'm'. It given by the formula

W = m x g newton

Where,

g - acceleration due to gravity.

Substituting the given values in the above equation

W = 1800 Kg x 9.8 m/s²

= 17640 N

Hence, the weight of the automobile, W = 17640 N

8 0

4 years ago

Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of unifo

fgiga [73]

The definition of gravitational potential energy would gravitate allows to find the answers for the energy of each object on the highest rung of the ladder are:

a) expression for gravitational potential energy is $U_p = m g \ \Delta y$

b) Energy value

* Body 1 U_p = 82 J

* Body 2 U_p = 38.6 J

* Body 3 18.5 J

The gravitational potential energy is a configuration energy that represents the amount of work that the system can do for a given configuration, its expression is

$U_p = m g \ \Delta y$

Where $U_p$ is the gravitational potential energy, m the mass of the body and Δy the difference in height.

In this case it indicates that the minimum height is at the bottom and is equal to zero, the steps of a ladder have a height of approximately y = 15 cm = 0.15 m

They indicate the mass of the bodies are m₁ = 3.10 kg, the mass of the body 2 m₂ = 1.46 kg , the mass of the third object is not observed, suppose it is m₃ = 0.7 kg.

They indicate that the body is placed on the last step, suppose it is a standard 18-step ladder, therefore the total height is

y = # _ steps y_each step

y = 18 0.15

y = 2.70 m

the gravitational potential energy to the capacity of the body is

body 1

$U_p$ = m₁ g Δy₁

U_p = 3.10 9.8 (2.70 -0)

U_p = 82 J

body 2

U_p = 1.46 9.8 ( 2.7-0)

U_p = 38.6 J

body 3

U_pUp = 0.70 9.8 (2.7-0)

U_p = 18.5 J

In conclusion, using the definition of gravitational potential energy, we can find the answers for the energy of each object on the highest rung of the ladder are;

a) expression for gravitational potential energy is $U_p = m g \ \Delta y$

b) Energy value

* Body 1 U_p = 82.0 J

* Body 2 U_p = 38.6 J

* Body 3 U_p = 18.5 J

Learn more here: brainly.com/question/3884855

8 0

3 years ago

A loop circuit has a resistance of R1 and a current of 1.9 A. The current is reduced to 1.5 A when an additional 3.1 Ω resistor

Deffense [45]

Answer:

11.625 Ohm

Explanation:

Let V be the Voltage charge of the loop, as this is constant we know that before the resistor addition the current I is:

V/R1 = 1.9 or V = 1.9R1

After the resistor addition to series R = R1 + 3.1

I = V/R = V/(R1 + 3.1) = 1.5

We can substitute V = 1.9R1

1.9R1 = 1.5R1 + 1.5*3.1

0.4R1 = 4.65

R1 = 4.65/0.4 = 11.625 Ohm

4 0

4 years ago

a charge of 4.5 times 10 to the negative 5 C is placed in an electric field with a strength of 2.0 times 10 to the 4 N over C. i

Rama09 [41]

Answer:

Explanation:

7 0

3 years ago