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vampirchik [111]
3 years ago
5

Give an example of free fall​

Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer:

A stone that is dropped down into an empty well

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Overload refers to: A. Performing a weight-lifting exercise with the resistance (load) held overhead B. Using a demand (load) ab
andrey2020 [161]

Answer:

E. All of the answers are correct

Explanation:

Overload principle in fitness training is associated with a gradual development of an athlete's abilities by progressively increasing the athlete's load and training.

In order to do this, the athlete's limit must be surpassed albeit gradually at first then picked up later over time.

6 0
3 years ago
Determine the force of gravity on a 1600 kg spaceship: near the surface of the Moon.
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yahoo has the answer im telling you

Explanation:

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3 years ago
A railroad car of 2000 kg coasting at 3.0 m/s overtakes and locks with an identical car coasting on the same track in the same d
serg [7]
The key is in "they lock together". This tells you this is a complete inelastic collision and therefore you can use the formula:
m1*v1+m2*v2=v(m1+m2)
Plug in numbers:
2000*3+2000*2=v(2000+2000)
so v=2 m/s, obviously in the same direction of motion in which they were both moving.
4 0
4 years ago
El tren Lima la Orolla va a una velocidad de 10 km/h y de pronto aplica el freno por un derrumbe en la via. Si demora 18 segundo
Naya [18.7K]

Answer:

Distancia = 50.04 metros

Explanation:

Dados los siguientes datos;

Velocidad = 10 km/h

Tiempo = 18 segundos

Para encontrar la distancia;

Conversión:

10 km/h = 10 * 1000/3600 = 2.78 m/s

Distancia = velocidad * tiempo

Distancia = 2.78 * 18

Distancia = 50.04 metros

Por lo tanto, el tren viajaría 50.04 metros antes de detenerse por completo.

7 0
3 years ago
1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential
cupoosta [38]
<h3>Answer:</h3>

\displaystyle U_s = 0.6 \ J

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Physics</u>

<u>Energy</u>

Elastic Potential Energy: \displaystyle U_s = \frac{1}{2} k \triangle x^2

  • U is energy (in J)
  • k is spring constant (in N/m)
  • Δx is displacement from equilibrium (in m)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

k  = 7.50 N/m

Δx = 0.40 m

<u>Step 2: Find Potential Energy</u>

  1. Substitute in variables [Elastic Potential Energy]:                                        \displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2
  2. Evaluate exponents:                                                                                      \displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)
  3. Multiply:                                                                                                           \displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)
  4. Multiply:                                                                                                           \displaystyle U_s = 0.6 \ J
6 0
3 years ago
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