<span>So we wan't to know what is the velocity after a collision of two railroad cars, one moving to the east and the other moving to the west if m1=2000kg, v1=5m/s and m2=6000kg, v2=3m/s. We can find the solution using the law of conservation of momentum for plastic collisions that states that the momentum must remain constant before (left side of the equation) and after (right side of the equation) the collision: m1*v1+m2*v2=(m1+m2)*v. So now we simply plug in the numbers and get: 2000kg * 5m/s + 6000kg * 3m/s = (2000kg + 6000kg)*v. Now we can write: 10000 kgm/s + 18000 kgm/s = 8000kg * v. To get v, the velocity of both railroad cars after the collision we simply divide both sides of the equation with 8000 kg: so v=3.5m/s to the west. </span>
The ratio of intensity to distance is an inverse square law so if you increase the distance by 3 times, the intensity will reduce by
times
so the intensity will be 9 times less.
Answer:
1500 J
Explanation:
Apparently, we're to assume that no energy is lost to friction or other effects. Then all of the energy the train has is due to work being done on it.
1500 J of work was done on the train
The mass of the water with the sugar dissolved in it is 55 grams. This is because when you add the weight of the water, and the sugar that you added, it is 55.