Replace <span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> with <span>yy</span>.<span><span>y=<span>x2</span>−1</span><span>y=<span>x2</span>-1
</span></span>Interchange the variables.<span><span>x=<span>y2</span>−1</span><span>x=<span>y2</span>-1
</span></span>Solve for <span>yy</span>.
<span><span>y=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span>y=<span>1+x</span>,-<span>1+x
</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span><span>(x)</span></span></span>.
<span><span><span>This is your answer=f<span>−1</span></span><span>(x)</span>=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span><span>f<span>-1</span></span><span>(x)</span>=<span>1+x</span>,-<span>1+x
Hope you have a wonderful day! hope this helps!
</span></span></span>
Answer:
6 tablespoons of baking soda
Step-by-step explanation:
There are 8 fluid ounces in 1 cup and shes going to use half a cup so that means shes going to use 4 fluid ounces of vinegar. To find how much baking soda she is going to use, we are going to multiply.
1.5 * 4 = 6
Best of Luck!
Answer:
y = 3
Step-by-step explanation:
Let's start with the left side of the equation.
5(y-2)-2= 2(y+1)-5
5y-10-2= 2(y+1)-5
Now let's solve the right side
5y-10-2= 2y+2-5
5y-12= 2y-3
-2y -2y
3y-12=-3
+12 +12
3y = 9
3y/3 = 9/3
y = 3
hope this helps!
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)