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2 years ago

9

Put the following equation of a line into slope-intercept form, simplifying all fractions.

2 answers:

baherus [9]2 years ago

5 0

Answer: y=-3/2x+3

Step-by-step explanation:

First subtract 3x from both sides to start isolating the y.

Then you get 2y=-3x+6

Divide both sides by 2 to get y alone and you get

y=-3/2x+3

Sveta_85 [38]2 years ago

3 0

Y=-3/2x+3

here is the answer

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Solve 7 8 and 9 please

VLD [36.1K]

7) y = 4x
8) y = 7x/8
9) y = 25x/3

I think this are the answers.

7 0

3 years ago

Read 2 more answers

What kind of sequence is the pattern 15, 17, 20, 24, 29,

VikaD [51]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: 15, 17, 20, 24, 29,35, 42}}}}}}$

$\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}$

$\: 15, 17, 20, 24, 29,35, 42$

➺ $\: 15 + 2 = 17$

➺ $\: 17 + 3 = 20$

➺ $\: 20 + 4 = 24$

➺ $\: 24 + 5 = 29$

➺ $\: 29 + 6 = 35$

➺ $\: 35 + 7 = 42$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

7 0

3 years ago

The integer<br> is neither positive nor negative.

Artist 52 [7]

Answer:

false

Step-by-step explanation:

an integer is any number greater or less than 0

8 0

3 years ago

If we wanted to create a new 90% confidence interval from a different sample for the proportion of those with a two on one date

slava [35]

Answer: 271

Step-by-step explanation:

The formula we use to find the sample size is given by :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

, where $z_{\alpha/2}$ is the two-tailed z-value for significance level of $(\alpha)$

p = prior estimation of the proportion

E = Margin of error.

If prior estimation of the proportion is unknown, then we take p= 0.5 , the formula becomes

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2$

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2$

Given : Margin of error : E= 0.05

Confidence level = 90%

Significance level $\alpha=1-0.90=0.10$

Using z-value table , Two-tailed z-value for significance level of $0.10$

$z_{\alpha/2}=1.645$

Then, the required sample size would be :

$n=0.25(\dfrac{1.645}{0.05})^2$

Simplify,

$n=270.6025\approx271$

Hence, the required minimum sample size =271

3 0

3 years ago

How much 20% solution needs to be added to a 60% solution to make 400 ml of a 40% solution

Scorpion4ik [409]

Let $x$ be the volume of 20% solution, $y$ the volume of the 60% solution. We want a total volume of 400 mL in the final mixture, so

$x+y=400$

Each mL of either solution will contribute a corresponding concentration, and in the final mixture we want the 400 mL to have a 40% concentration, which means we should also have

$0.2x+0.6y=0.4\times400=160$

Solve the system and we get $x=y=200\,\rm{mL}$ .

4 0

3 years ago