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Anni [7]
3 years ago
15

How many degrees and in what direction was the figure rotated?

Mathematics
1 answer:
Deffense [45]3 years ago
5 0

Answer: 90 degrees clockwise

Step-by-step explanation:

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A hat contains several slips of paper with names. Each name is written on one or more slips. Grace chooses a slip of paper from
7nadin3 [17]

Answer:

You have at least a 1 out of 40 chance that your name will be drown

Step-by-step explanation:

4 0
3 years ago
Daniel works in a market. He has a large bag of potatoes that weighs 261/4 pounds and he is going to sell them in smaller bags o
Lynna [10]

Answer:

11 6/9

Step-by-step explanation:

Daniel works in a market

He has large bags of potatoes that weighs 26 1/4

Daniel is going to sell them in smaller bags 9/4 pounds each

Therefore the number of smaller bags of potatoes in which Daniel would have filled can be calculated as follows

= 26 1/4 ÷ 9/4

= 105/4 ÷ 9/4

= 105/4 × 4/9

= 105/9

= 11 6/9

7 0
3 years ago
Mary says the pen for her horse is an acute right triangle. Is this possible?
Andrew [12]
We know that
An acute triangle is a triangle with all three angles acute (less than 90 degree ).

An obtuse triangle is one with one obtuse angle (greater than 90 degree) and two acute angles.

A right triangle is one with one right angle (angle equal to 90 degree ) and two acute angles.

therefore

The answer is

Is not possible
6 0
3 years ago
What is the slope of the line through (3, 3) and (0, 12)? Pls help due soon
Lapatulllka [165]

Answer:

y=-3x+12 equation of line

however slope is -3

Step-by-step explanation:

y=mx+c

(12-3)/(0-3)=9/-3=-3

y=-3x+c

3=-3(3)+c

3=-9+c

+9

12=c

y=-3x+12

3 0
3 years ago
Given the foci of (8,0) and the difference of the focal radii = 6, find the equation of the hyperbola
k0ka [10]

Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

2c = 8 - (-8)

c = 8

Also, difference between the foci or focal distance is given by :

2a = 6

a = 3

Now, we know for hyperbola :

b^2 +a^2 = c^2\\\\b^2={c^2-a^2}\\\\b^2 = 64-9\\\\b^2 = 55

General equation of hyperbola is :

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1

Hence, this is the required solution.

3 0
3 years ago
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