Answer:
{"double", "char", "char", "double"} will be stored in word.
Explanation:
Given the word is an array of four strings, {"algorithm", "boolean", "char", "double"}. Hence, the length of the word array is 4.
The for-loop will only run for two iterations due to i < word.length/2, with i = 0 (first loop) and i = 1 (second loop).
In the first loop,
- word[word.length - 1 - i] = word[4 - 1 - 0] = word[3] = "double"
- Hence, the string "double" will be assigned to word[0] and overwrite "algorithm"
In the second loop,
- word[word.length - 1 - i] = word[4 - 1 - 1] = word[2] = "char"
- Hence, the string "char" will be assigned to word[1] and overwrite "boolean"
At last, the word array will hold {"double", "char", "char", "double"}
It means the sound cord, or axu is shot for auxiliary.
Answer:
3-using a wild card in your search
Answer:
The answer is "Option a".
Explanation:
A score can be detrimental. When an element has a score below zero, it means, that the sequences up to this point have no correlations, that are set to zero and its effects the previous alignment is excluded. Thus, alignment can be further found in every position later in the calculation. and other options are incorrect that can be described as follows:
- In option b, In this option the score can be negative, that's why we can't set its value.
- In option c, The first row and column must contain some value it can't be 0, that's why it is not correct.
- In option d, It will start with a lower score and ends with a higher score, that's why it is not correct.
