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Dahasolnce [82]
3 years ago
15

2.) Which is an equation? *

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

B is your answer ok bro

didn't ask like this questions

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LITTERLY HELP ME PLEASEE..... 2/x-4x/2x-3=-2<br> PLEASEE I INSERTED A PIC
Stels [109]

Answer:

x = -3

Step-by-step explanation:

Given expression is,

\frac{2}{x}- \frac{4x}{2x-3}=-2

\frac{2(2x-3)}{x(2x-3)}-\frac{4x(x)}{x(2x-3)}=-2

\frac{2(2x-3)-4x^{2} }{x(2x-3)}=-2

(4x - 6) - 4x² = -2x(2x - 3)

4x - 6 - 4x² = -4x² + 6x

4x - 6 = 6x

6x - 4x = -6

2x = -6

x = -3

3 0
3 years ago
kims age is twice of her sister when you add to her sisters age you get 3 how old is each sister (a) write an equation that repr
Lina20 [59]
Kim is 2. Her sister is 1 years old. 2+1=3
6 0
2 years ago
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
Unit 17- calculations
OLEGan [10]

What exactly is your question?

4 0
2 years ago
Read 2 more answers
I need help please!!
Sergio039 [100]

Answer:

16 cm2

Step-by-step explanation:

By equa tion of area of triangle: S = 1/2 * height * base

Triangle B: 32  = 1/2 * 8 * x --> x = 8 (cm)

The base of triangle A is half of the base of triangle B so it is 4 cm.

The area of triangle A = 1/2 * 8 * 4 = 16 (cm2)

5 0
2 years ago
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