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Semenov [28]
3 years ago
14

"What is Limit as x approaches 2h(x), if it exists?"

Mathematics
2 answers:
s2008m [1.1K]3 years ago
4 0
I think it is 3 as a possible answer
LuckyWell [14K]3 years ago
3 0

The limit as <em>x</em> → 2 is 0. This is determined by the behavior of the blue-ish curve around <em>x</em> = 2.

When you're talking about a limit as <em>x</em> approaches some value <em>c</em>, you're really considering values of <em>x</em> ≠ <em>c</em> but very close to <em>c</em>. In this case, the blue-ish curve captures what happens around <em>x</em> = 2. To the left, the curve is falling toward 0, and to the right, the curve is falling further down from 0. The fact that <em>f</em> (2) = 3 (according to the green dot) has no effect on the value of the limit.

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Misha Larkins [42]
The answer is 7.

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3 0
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Delicious77 [7]
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.

For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
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Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
9/sin54° =  11/sinB
B = 80.4°

9/sin54° = 8/sinC
C = 45.6°

The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
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Step-by-step explanation:

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Answer:

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