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3 years ago

Help <3 ;3

2 answers:

8 0

Hello,

Rational numbers are numbers that can be represented by fractions that consist of integers.

In this case, B. -7/3 is already a fraction that consists of integers, so it is a rational number.
C. square 3 is = $3^{2}$ = 9, which can be represented by 9/1, so it is also a rational number.

A and D are incorrect as they cannot be represented by fractions that consist of integers.

The answers are B and C.

Hope this helps!

diamong [38]3 years ago

5 0

Answer:

A. 2.77777...

$B. -\frac{7}{3}$

Step-by-step explanation:

A rational number can be written in the form $\frac{a}{b}$ ,where $b\ne 0$ and $a,b$ are integers.

The number $2.77777...$ can be rewritten as $\frac{25}{9}$ .

This is a rational number.

$-\frac{7}{3}$ is also a rational number.

$\sqrt{3}=1.73205080...$

No recurring pattern so it is an irrational number

$2.7182818459....$ also has no recurring pattern. This is also an irrational number.

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A circle is centered at N(-6, -2). The point E(-1,1) is on the circle.

galina1969 [7]

Answer:

Outside the circle

Step-by-step explanation:

Let's first write the equation of this circle: $(x-h)^2+(y-k)^2=r^2$ , where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:

NE = $\sqrt{(-6-(-1))^2+(-2-1)^2} =\sqrt{25+9} =\sqrt{34}$

The radius is √34, which means that r² = 34. So, our equation is:

(x + 6)² + (y + 2)² = 34

Plug in -10 for x and -7 for y:

(x + 6)² + (y + 2)² = 34

x² + 12x + 36 + y² + 4y + 4 = 34

x² + 12x + y² + 4y + 40 = 34

x² + 12x + y² + 4y + 6 = 0

(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7

Since 7 > 0, we know that H lies outside the circle.

6 0

3 years ago

Read 2 more answers

Find and simplify each of the following for

WINSTONCH [101]

Answer:

(A) f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

(B) f(x + h) - f(x) = 8xh + 4h² - 6h

Step-by-step explanation:

* Lets explain how to solve the problem

- The function f(x) = 4x² - 6x + 6

- To find f(x + h) substitute x in the function by (x + h)

∵ f(x) = 4x² - 6x + 6

∴ f(x + h) = 4(x + h)² - 6(x + h) + 6

- Lets simplify 4(x + h)²

∵ (x + h)² = (x)(x) + 2(x)(h) + (h)(h) = x² + 2xh + h²

∴ 4(x + h)² = 4(x² + 2xh + h²) = 4x² + 8xh + 4h²

- Lets simplify 6(x + h)

∵ 6(x + h) = 6(x) + 6(h)

∴ 6(x + h) = 6x + 6h

∴ f(x + h) = 4x² + 8xh + 4h² - (6x + 6h) + 6

- Remember (-)(+) = (-)

∴ f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

* (A) f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

- Lets find f(x + h) - f(x)

∵ f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

∵ f(x) = 4x² - 6x + 6

∴ f(x + h) - f(x) = 4x² + 8xh + 4h² - 6x - 6h + 6 - (4x² - 6x + 6)

- Remember (-)(-) = (+)

∴ f(x + h) - f(x) = 4x² + 8xh + 4h² - 6x - 6h + 6 - 4x² + 6x - 6

- Simplify by adding the like terms

∴ f(x + h) - f(x) = (4x² - 4x²) + 8xh + 4h² + (- 6x + 6x) - 6h + (6 - 6)

∴ f(x + h) - f(x) = 8xh + 4h² - 6h

* (B) f(x + h) - f(x) = 8xh + 4h² - 6h

- Lets find $\frac{f(x+h)-f(x)}{h}$

∵ f(x + h) - f(x) = 8xh + 4h² - 6h

∴ $\frac{f(x+h)-f(x)}{h}=\frac{8xh + 4h^{2}-6h}{h}$

- Simplify by separate the three terms

∴ $\frac{f(x+h)-f(x)}{h}=\frac{8xh}{h}+\frac{4h^{2} }{h}-\frac{6h}{h}$

∴ $\frac{f(x+h)-f(x)}{h}=8x+4h-6$

* (C) $\frac{f(x+h)-f(x)}{h}=8x+4h-6$

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