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3 years ago

Help <3 ;3

2 answers:

8 0

Hello,

Rational numbers are numbers that can be represented by fractions that consist of integers.

In this case, B. -7/3 is already a fraction that consists of integers, so it is a rational number.
C. square 3 is = $3^{2}$ = 9, which can be represented by 9/1, so it is also a rational number.

A and D are incorrect as they cannot be represented by fractions that consist of integers.

The answers are B and C.

Hope this helps!

diamong [38]3 years ago

5 0

Answer:

A. 2.77777...

$B. -\frac{7}{3}$

Step-by-step explanation:

A rational number can be written in the form $\frac{a}{b}$ ,where $b\ne 0$ and $a,b$ are integers.

The number $2.77777...$ can be rewritten as $\frac{25}{9}$ .

This is a rational number.

$-\frac{7}{3}$ is also a rational number.

$\sqrt{3}=1.73205080...$

No recurring pattern so it is an irrational number

$2.7182818459....$ also has no recurring pattern. This is also an irrational number.

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Hi anyone know the answer to this? Ill give brainliest :(

Agata [3.3K]

The top one is the answer

4 0

2 years ago

suppose y varies directly with x and y=5 when x=20. Write a direct variation equation then find the value of x when y=3/2

jek_recluse [69]

X=k*Y
K*Y=X
K=X/Y
K=20/5
K=4

For Y=3/2
X=k*3/2
X=4*3/2
X=6

6 0

3 years ago

Check the true statements below:

valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d. In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0

3 years ago

Solve the simultaneous equations

nexus9112 [7]

Answer:

Step-by-step explanation:

2x + 3y = 2

x = 2 - 3y /2

x + y = 0

substitute the value of x

$\frac{2 \\- 3y}{2}$ + y = 0

2 - 3y + 2y = 0

2 = y

again,substitute the value of y

x = 2 - 3y / 2

=2 - 3*2 / 2

=2 - 6 / 2

=-2

6 0

2 years ago

what are the roots of the polynomial equation x3-7x=6x-12? Use a graphing calculator and a system of equations.

Masteriza [31]

X3-7x=6x-12
x3-7x-6x+12=0
x3-13x+12=0
(x-1)(x2+x-12)=0
Calculate delta of the second bracket:
delta = 1+4*12=49
sqrt(delta)=sqrt(49)=7
x_1=(-1-7)/2=-4
x_2=(-1+7)/2=3

(x-1)(x+4)(x-3)=0

Answear:
Roots: x=1, x=-4, x=3.

3 0

3 years ago

Read 2 more answers