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erastovalidia [21]
3 years ago
8

A line that includes the point (9, 10) has a slope of -1/9 what is its equation in point-slope

Mathematics
1 answer:
Molodets [167]3 years ago
7 0
You need to add by the root and then you will get the answer
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Can someone help me answer this
lions [1.4K]

Answer:

sum the numbers of favorite food together.

pizza- 58.

hamburger- 36.

pasta- 14.

others- 17.

Addition of the favorite food will give us .

58+36+14+17=125.

pizza ..58/125 × 100 =46.4

3 0
2 years ago
Plz help..............refresh the page before u answer
Anni [7]
To add/subtract fractions you need to have a common denominator...

(2/2)(4n/15)+(5/5)(n/6)

8n/30+5n/30

(8n+5n)/30

13n/30
8 0
4 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
An item is regularly priced at $69. David bought it at a discount of 55% off the regular price. How much did David pay?
zysi [14]

Answer:

37.95

Step-by-step explanation:

55% of $69

so 0.55 x 69 = 37.95

8 0
3 years ago
Read 2 more answers
Evaluate :<br> A. <img src="https://tex.z-dn.net/?f=x%5E%7Bx%5E3%7D%3D3" id="TexFormula1" title="x^{x^3}=3" alt="x^{x^3}=3" alig
sdas [7]

Answer:

<h3>A. </h3>
  • x^{x^3} = 3
  • log x^{x^3} = log 3
  • x³ log x = log 3
  • 3x³ log x = 3 log 3
  • x³ log x³ = log 3³
  • x^3^{x^3} = 3³
  • x³ = 3
  • x = 3^{1/3}
<h3>B.</h3>
  • 4ˣ + 6ˣ = 9ˣ
  • 2²ˣ + 2ˣ3ˣ = 3²ˣ

<u>Divide both sides by 2²ˣ</u>

  • 1 + (3/2)ˣ = (3/2)²ˣ

<u>Substitute (3/2)ˣ = t</u>

  • t² - t - 1 = 0

<u>Solve for t:</u>

  • t = (1  ± √5)/2

<u>Positive root is considered as (3/2)ˣ can't be negative.</u>

  • (3/2)ˣ = (1 + √5)/2
  • x = log [(1 + √5)/2] / log (3/2)
  • x = 1.18681439028

7 0
3 years ago
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