Please solve for x. Give a real answer and I’ll be really grateful ✨

Please help :( this is due today! Will be giving brainliest please HURRY!

timurjin [86]

Answer:

y=2.18x

Step-by-step explanation:

i got this answer by multiplying 2.18 x 3 which got me 6. so basically you need to multiply x, (which for the next one x will be 8) and multipy that with 2.18 which will get you 17.44. So basically the answer is A) y=2.18x. have a great day and please mark brainliest!

5 0

3 years ago

Read 2 more answers

Tom is reading an article about the population of a city. The anys exacoptom is 346,733 people

BabaBlast [244]

Answer:

346,733 rounded to the nearest thousand is 347,000

Step-by-step explanation:

the thing he did wrong was he rounded down instead of up, you should know to go up or down by looking at the hundreds and seeing if it's closer the last hundred or the next hundred.

7 0

3 years ago

A truck travels a constant speed of 20m/s . It then decelerates to rest in ten seconds. Find the total distance travelled by the

Darya [45]

In the first 10 seconds it is 200m
In the next 10 seconds (it is decelerating 2m/s every second) it is 100m

200m+100m=300m

300 meters is the answer

5 0

3 years ago

A Halloween trick-or-treat group consists of 3 Trolls, 4 Nazguls, 4 Ents, and 5 Pokemon. A committee of 4 is to be picked to rep

balu736 [363]

Answer:

The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357

Step-by-step explanation:

No. of Trolls = 3

No. of Nazguls =4

No. of Ents = 4

No. of Pokemon = 5

Total Monsters = 16

We are given that A committee of 4 is to be picked to represent the group at the Monster Bash.

(a) Find the probability that the committee will consist of 1 from each type of monster.

So, the probability that the committee will consist of 1 from each type of monster:

= $\frac{^3C_1 \times ^4C_1 \times ^4C_1 \times ^5C_1}{^{16}C_4}$

= $\frac{\frac{3!}{1!(3-1)!} \times \frac{4!}{1!(4-1)!} \times \frac{4!}{1!(4-1)!}\times \frac{5!}{1!(5-1)!}}{\frac{16!}{4!(16-4)!}}$

= $\frac{\frac{3!}{1!(2)!} \times \frac{4!}{1!(3)!} \times \frac{4!}{1!(3)!}\times \frac{5!}{1!(4)!}}{\frac{16!}{4!(12)!}}$

= $0.1318$

b)Suppose that the Pokemon refuse to be on the same committee as a the Trolls.

So, the probability that this type of committee is formed

= $\frac{(^3C_3 \times ^8C_1)+(^3C_2 \times ^8C_2)+(^3C_1 \times ^8C_3)+(^3C_0 \times ^8C_4)+(^5C_4 \times ^8C_0)+(^5C_3 \times ^8C_1)+(^5C_2 \times ^8C_2)+(^5C_1 \times ^8C_3)}{^{16}C_4}$

= $\frac{(\frac{3!}{3!(3-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{3!}{2!(3-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{3!}{1!(3-1)!} \times\frac{8!}{3!(8-3)!})+(\frac{3!}{0!(3-0)!} \times \frac{8!}{4!(8-4)!})+(\frac{5!}{4!(5-4)!} \times \frac{8!}{0!(8-0)!})+(\frac{5!}{3!(5-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{5!}{2!(5-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{5!}{1!(5-1)!} \times \frac{8!}{3!(8-3)!})}{\frac{16!}{4!(16-4)!}}$

= $0.5357$

Hence The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357

4 0

3 years ago

Will give brainlist if u answer answer ASAP

LuckyWell [14K]

I think it is B and C sorry if it’s not right but that’s what I think it is

8 0

3 years ago