Please help :( this is due today! Will be giving brainliest please HURRY!
2 answers:
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Answer:
a) 12
b) 18
c) 37
d) 97
Step-by-step explanation:
Toward the middle of the harvesting season, peaches for canning come in three types, early, late, and extra late, depending on the expected date of ripening. During a certain week, the following data were recorded at a fruit delivery station:
34 trucks went out carrying early peaches ;
61 carried late peaches ;
50 carried extra late;
25 carried early and late;
30 carried late and extra late;
8 carried early and extra late;
6 carried all three;
9 carried only figs (no peaches at all) .
<u>To solve this problem, the best solution is to drawn a Venn Diagram, which is attached.</u>
(a) How many trucks carried only late variety peaches?
12
(b) How many carried only extra late?
18
(c) How many carried only one type of peach ?
7+12+18 = 37
(d) How many trucks (in all) went out during the week?
Sum of all the numbers on the Diagram:
7+2+6+19+12+24+18+9= 97
Answer:
- m ≈ 8.165
- b ≈ 2.299
Step-by-step explanation:
It is convenient to let technology help out. Some graphing calculators will accommodate a model of your choice. Others are restricted to particular models, of which yours may not be one.
A spreadsheet solver may also offer the ability to optimize two variables at once. For that, you would write a function that gives the sum of the squares of the differences between your data points and those predicted by the model. You would ask the solver to minimize that sum.
If you want to do this "the old-fashioned way," you would write the same "sum of squares" function and differentiate it with respect to m and b. Solve the simultaneous equations that make those derivatives zero. (My solver finds multiple solutions, so the neighborhood needs to be restricted in some way. For example m > 0, b > 0, or sum of squares < 1.)
