Look at the table below.

olga55 [171]

For this question, all you have to do is combine like terms. I am assuming that the 3x2 and 5x2 are exponents, so they are one pair and then -4x and 8x are the other. The rule is the higher exponent goes first, so here is what it looks like:

3x2 - 4x - 5x2 +8x

First combine the numbers with exponents, 3x2-5x2, you always bring over the positive or negative, which ever it may be, in this case, since it is -5x2, you bring that over.

3x2-5x2=-2x2

Now to do the number with matching letters, -4x+8x= 4x

Now just bring the problem back together:

-2x2+4x

That is your simplified answer: -2x2+4x.

5 0

3 years ago

Read 2 more answers

Riverside Elementary School is holding a school-wide election to choose a school color. Five-eighths of the votes were for blue,

Mnenie [13.5K]

Answer:

Step-by-step explanation:

Let the total number of votes to choose a color = x

Number of votes for blue = $\frac{5}{8}\times x$

Remaining votes = x - $\frac{5}{8}\times x$

= $\frac{8x-5x}{8}\times x$

= $\frac{3}{8}\times x$

Votes for green = $\frac{5}{9}\times (\text{Remaining votes})}$

= $\frac{5}{9}\times \frac{3x}{8}$

= $\frac{5}{24}\times x$

Finally remaining votes = $\frac{3x}{8}-\frac{5x}{24}$

= $\frac{9x-5x}{24}$

= $\frac{4x}{24}$

= $\frac{x}{6}$

Since these votes are for red therefore,

$\frac{x}{6}$ = 48

x = 48×6

= 288

a) Votes for blue are $\frac{5x}{8}$

Therefore, exact number for blue votes = $\frac{5\times 288}{8}$

= 5×36

= 180

b). Votes for green = $\frac{5x}{24}$

= $\frac{5\times 288}{24}$

= 60

c). Since 25 students were absent on that day of the vote, number of students at Riverside Elementary School = 288 + 25

= 313

d). Since seven tenths of the votes for blue were made by the girls.

Therefore, number of girls voted for blue = $\frac{7}{10}\times 180$

= 7×18

= 126

Since total votes made = 288

Therefore, half of the votes made = $\frac{288}{2}$

= 144

Now it's clear that number of votes made by girls is less than half of all the votes.

e). 126 girls voted for blue.

5 0

3 years ago

6/9 in a percentage

motikmotik

Answer:

66.666%

Step-by-step explanation:

6/9=x/100

9x=6x100

9x=600

x=600:9

x=66.666

66.666/100=66.666%

3 0

2 years ago

Read 2 more answers

It took my question down twice here's a real math question I guess

aliina [53]

Answer:

$n-3$

Interval notation: $(-\infty, -10)\cup(-3,\infty)$

Step-by-step explanation:

First inequality:

$n+8$

Therefore, this inequality restricts:

$n \in \mathrm{R};\: n$

Second inequality:

$< 8+n-3$

Therefore, this inequality restricts:

$n \in \mathrm{R};\: n>-3$

Therefore, with both of these restrictions together, we have:

$\fbox{$n \in \mathrm{R}; n-3$}\\\mathrm{or\:}\fbox{$n-3$}\\\mathrm{or\:}\fbox{$(-\infty, -10)\cup(-3,\infty)$}$ .

4 0

3 years ago

A dance class consists of 22 students, of which 10 are women and 12 are men. if 5 men and 5 women are to be chosen and then pair

OverLord2011 [107]

solution:

I choose 5 women from a pool of 10 in 10C2 ways.

I choose 5 men from a pool of 12 in 12C2 ways.

So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.

But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!

So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.

3 0

4 years ago