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3 years ago

How do you find the width of a rectangle

Mathematics

2 answers:

shepuryov [24]3 years ago

4 0

W= P / 2 - L

Width= Perimeter over 2 subtracted by length

irina [24]3 years ago

4 0

You need to know the length or perimeter

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What is the smallest Square number using 5 roman numerals?

In-s [12.5K]

Answer:

The answer is "1"

Step-by-step explanation:

Let 5 roman numbers are:

$\to I=1\\\\\to II=2\\\\\to III=3\\\\\to IV= 4\\\\\to V=5$

There square values are as follows:

$\to 1^2=1\\\\\to 2^2=4\\\\\to 3^2=6\\\\\to 4^2=16\\\\\to 5^2=25$

The smallest square number is= 1.

3 0

3 years ago

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

1 year ago

What constant acceleration is required to increase the speed of a car from 30 mi/h to 52 mi/h in 5 seconds? (Round your answer t

Alenkasestr [34]

Answer:

$a = 9.84 m/s^2$

Step-by-step explanation:

Given:

Initial speed (Vi) = 30 mi/h = 67.1 m/s

Final speed (Vf) = 52 mi/h = 116.32

Time period(t) = 5 seconds

We know the formula of acceleration in terms of initial speed, final speed and time:

$a = \frac{Vf -Vi}{t}$

$a = \frac{116.32-67.10}{5}$

$a = 9.84 m/s^2$

6 0

3 years ago

The Chicago Bears

Arada [10]

Answer:

I believe the answer is 8 to 8 (8/8) or 1

Step-by-step explanation:

16-8=8

Wins= 8

Loses= 8

Ratio= 8/8

8/8= 1

The answer depends how the question asks for it, so its either 8 to 8, or 1

5 0

3 years ago

Read 2 more answers

In ΔQRS, s = 26 cm, r = 23 cm and ∠R=157°. Find all possible values of ∠S, to the nearest degree.

kobusy [5.1K]

Answer:

No Solution

Explanation:

Since angle R is an obtuse angle, side r has to be the longest in length, but it isn't, so it can't form a triangle

6 0

3 years ago