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3 years ago

4(x + 1) + 8 = 24 how do i solve this

Mathematics

2 answers:

ivanzaharov [21]3 years ago

7 0

Answer: x = 3

First, you can multiply the 4 with the x and the 1:

4x + 4 + 8 = 24

Now, you just add the 4 and the 8 together:

4x + 12 = 24

Subtract 12 from both sides:

4x = 12

Now you divide by 4 from both sides

x = 3

^ and that's your final answer!

Sergio039 [100]3 years ago

5 0

Answer:

x=3

Step-by-step explanation:

4x+4+8=24

4x+12=24

4x=12

4x/4=12/4

(x=3)

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What are the possible rational roots of the polynomial equation? 0=2x7+3x5−9x2+6

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Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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