Answer:
x=6
Step-by-step explanation:
log(5x+10)-log(4x+12)=1-2log(3)
log(5x+10/4x+12)=1-2log(3)
log(5x+10/4x+12)=log(10)+log(3^-2)
log(5x+10/4x+12)=log(10×3^-2)
log(5x+10/4x+12)=log(10×1/9)
log(5x+10/4x+12)=log(10/9)
5x+10/4x+12=10/9
9(5x+10)=(4x+12)10
45x+90=40x+120
5x=30
x=6
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Answer:
-6
Step-by-step explanation:
The equation is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
The y intercept is the value when x = 0
The y value is -6 when the x value is 0
y = -4x+ (-6)
Answer:
8
Step-by-step explanation:
The answer is 0.690129 hope this helps:)
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .