Answer:
Not the same.
Step-by-step explanation:
Given that there is a rotation of 180 degrees . To check whether this is a reflection over the y axis.
Reflection over the y axis make the coordinates (x,y) as (-x,y)
i.e. this means rotation of 180 degrees about the origin anticlockwise.
Hence just rotation of 180 degrees is not the same as a reflection over y axis.
The conditions are:
i) 180 degree to be rotated anticlockwise
ii) Rotation is about the origin
Hence a rotation of 180 degrees need not always be the same as reflection over y axis.
Answer:
Part 1:
or 
Part 2: 
Step-by-step explanation:
To start things off, you must put everything on the opposite side of y so that you only have the y variable left.
In this case, put x onto the other side, making it negative since it's flipped, so you get
(since the x is negative you're using subtraction from 11).
Next, divide both sides by 5 to make 5y into y:


Then in this case you turn y=f(x), but the system did it for you, so all you have to put is
.
For the second part you must replace x with 2 since you need to find f(2).

Your answer for part 2 is
.
This is adding two vectors, one magnitude 300 direction east, and one magnitude 100 direction 30 degrees northeast.
For the resulting sum we can use the Law of Cosines or just add up the components. Let's try it both ways.
Components first. In the east direction we have
300 + 100 cos 30° = 300 + 100(√3/2) = 386.60 miles per hour
In the north direction we have
0 + 100 sin 30° = 100 (1/2) = 50 miles per hour
So a total speed of
sqrt{386.6^2 + 50^2} = 389.82 miles per hour
Answer: 389.82
--------
OK let's try the Law of Cosines. We have sides 300 and 100 and included angle 150°.


69 - 3a = 0
69 - 3a (-69) = 0 (-69)
-3a = -69
-3a(/-3) = -69(/-3)
a = 23
hope this helps