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Gnoma [55]
3 years ago
15

Please help me on this question if you would want brianleist!! Tank yah!! ^^

Mathematics
2 answers:
Olenka [21]3 years ago
4 0

Answer:

answer is 6,7

Step-by-step explanation:

The x axis always comes before the y axis.

Lesechka [4]3 years ago
3 0

Answer: And the answer is b 6,7

Step-by-step explanation:

Did you meant “Please help me on this question if you would want brainliest!! Thank you!!”

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LekaFEV [45]
400 - 226 + 100 - x = 78
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6 0
3 years ago
Read 2 more answers
The ray GJ is the angle bisector of FGH and m FGH = 75.Enter m FGJ
White raven [17]

Answer:

m∠FGJ=37.5°

Step-by-step explanation:

we know that

m∠FGH=75°

m∠FGH=m∠FGJ+m∠JGH

so

75°=m∠FGJ+m∠JGH ------> equation A

If the ray GJ is the angle bisector of angle FGH

then

m∠FGJ=m∠JGH ----> equation B

substitute equation B in equation A and solve for m∠FGJ

75°=2(m∠FGJ)

Divide by 2 both sides

m∠FGJ=37.5°

7 0
3 years ago
The regions of the parietal lobes that are involved in mathematical and spatial reasoning are known as
GuDViN [60]

Answer: Association areas.

Step-by-step explanation:

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5 0
3 years ago
A marathon is 26.2 miles long there’s a water station every 1.31 miles along the race route which expression repeats the total n
omeli [17]

Answer:

26.2/1.31

Step-by-step explanation:

6 0
4 years ago
What is the volume of a pyramid with an equilateral triangle for a base and a height equal to the base side length? Express your
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\bf \begin{array}{llll} \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}\qquad \begin{cases} s=length~of\\ \qquad a~side \end{cases} \end{array}\qquad \begin{array}{llll} \textit{volume of a pyramid}\\\\ V=\cfrac{Bh}{3}~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\cfrac{s^2\sqrt{3}}{4}\\[1em] h=s \end{cases} \end{array}


\bf V=\cfrac{~~\left( \frac{s^2\sqrt{3}}{4} \right)(s)~~}{3}\implies V=\cfrac{~~\frac{s^3\sqrt{3}}{4}~~}{\frac{3}{1}} \\\\\\ V=\cfrac{s^3\sqrt{3}}{4}\cdot \cfrac{1}{3}\implies V=\cfrac{s^3\sqrt{3}}{12}

5 0
3 years ago
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