Answer:
y+k/x
Step-by-step explanation:
Aside from lowering worker productivity, artificial light sources are also costly, typically constituting anywhere from 25 to 50 per cent of a building’s energy use.
<h3>What are Artificial light sources?</h3>
In the late 19th and early 20th centuries, electric energy sources were used to generate artificial lighting. The goal of technological development for artificial lighting is to create light that will approximate natural sunshine (sunlight). The frequency range of an artificial light source and the intensity of illumination, expressed in lumens, are the two metrics used to measure artificial light. According to its progressive generation and the technology that made it possible, artificial light can be divided into three main sources.
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<h2>
<u>Sol</u><u>ution</u><u>:</u></h2>
Equation: x² + 10x + 21
<u>Step</u><u> </u><u>1</u><u>:</u> Find two numbers that can add up to 10 and be multiplied to 21. We have: 7 & 3, in the sense that 7+3=10, and 7×3=21. Replacing 10 with 7+3, the equation is now → x² + 7x + 3x + 21
<u>Step</u><u> </u><u>2</u><u>:</u> Get the new equation bracketed → (x² + 7x) (+3x + 21)
<u>Step</u><u> </u><u>3</u><u>:</u> Use 'x' in the equation. For the first part, we have 'x'. x² = x × x so, bring out one x out side the bracket, divide 7x by = 7 → x (x +7). Do the same for the second part by dividing 21 by 3 = 7, and then bringing out 3 from the bracket → 3 (x + 7).
Bringing everything together, we have: x(x+7) +3(x+7) → (x+3) (x+7)
<h3>
<u>Final</u><u> </u><u>ans</u><u>wer</u><u>:</u></h3>
(x+3) (x+7)
<h3 />
Divide 8/9 by 1/9 to get 8 meters per minute
Answer:
mAB = 7
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Set up equation.</em>
mAB + mBC = mAC
x + 4 + 4 = 3x + 2
<u>Step 2: Solve for </u><em><u>x</u></em>
- Combine like terms: x + 8 = 3x + 2
- Isolate <em>x</em> terms: 8 = 2x + 2
- Isolate <em>x </em>term: 6 = 2x
- Isolate <em>x</em>: 3 = x
- Rewrite: x = 3
<u>Step 3: Find AB</u>
- Define: mAB = x + 4
- Substitute in <em>x</em>: mAB = 3 + 4
- Add: mAB = 7
