Y = x² + 4x - 5
y = 2x
x² + 4x - 5 = 2x
<u> - 2x - 2x</u>
x² + 2x - 5 = 0
x = <u>-(2) ± √((2)² - 4(1)(-5))</u>
2(1)
x = <u>-2 ± √(4 + 20)</u>
2
x = <u>-2 ± √(24)
</u> 2
x = <u>-2 ± 2√(6)</u>
2
x = -1 ± √(6)
x = -1 + √(6) U x = -1 - √(6)
y = 2x
y = 2(-1 ± √(6))
y = 2(-1) ± 2√(6)
y = -2 ± 2√(6)
(x, y) = (-1 ± √(6), -2 ± 2√(6))
<u />
Answer: YES.
<span>Drawing a vertical line will cross the graph at one point only.
</span>
<span>Every x was assigned one y.</span>
<h3>
<u>Explanation</u></h3>
- Given the system of equations.

- Substitute y = -4x in the second equation.

- Substitute the value of x in any given equations. I will substitute the value of x in the first equation.

- Answer Check by substituting both values in two equations.
<u>First</u><u> </u><u>Equation</u>

<u>Second</u><u> </u><u>Equation</u>

Both equations are true for the value of x and value of y.
<h3>
<u>Answer</u></h3>
<u>
</u>
<u>Coordinate</u><u> </u><u>Point</u><u> </u><u>form</u>
<u>
</u>
Answer:
C
Step-by-step explanation:
5 - 1 = 4
5 - 5 = 0
5 - -1 = 6
I hope this helps but the answer most likely is C