Answer:
The number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40.
Step-by-step explanation:
IMPORTANT INFORMATION: The number of noncommercial orbital launches was two more than twice the number of commercial orbital launches.
Let's say that the number of commercial orbital launches is equal to x. Now, the number of noncommercial orbital launches is equal to 2x+2.
We are told that if we add the number of commercial and noncommercial orbital launches together we will get 59.
Therefore, if we add 2x+2 with x we should get 59:
2x+2+x=59
3x+2=59
3x=57
x=19
This is how we can come to the answer that the number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40 (2x+2=2*19+2=38+2=40).
Hope this helps!
Step-by-step explanation:
- y=(4×2)+5
y=8+5
<u>Y=1</u><u>3</u>
2. 4=4x+5
4x=4-5
<u>4</u><u>x</u>= <u>-1</u>
4. 4
x= <u>-1</u>
4
Deal 1 is the better deal because if it was $100, then 1 would be $60 and 2 would be $65.
Answer:
r = - 2
Step-by-step explanation:
Calculate the slope m using the slope formula and equate to 
m = 
with (x₁, y₁ ) = (- 9, - 3) and (x₂, y₂ ) = (- 2, r)
m = 
, that is
= ( cross- multiply )
7(r + 3) = 7 ( divide both sides by 7 )
r + 3 = 1 ( subtract 3 from both sides )
r = - 2
I would say D. I’m not really sure though. I’m only in 8th grade.
