Answer:
Step-by-step explanation:
If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes
I changed your x's to t's since t is for time.
Now we need to factor that quadratic and solve for time:
![0=-2(t^2-2t-8)](https://tex.z-dn.net/?f=0%3D-2%28t%5E2-2t-8%29)
Since -2 definitely does not equal 0, then
![t^2-2t-8=0](https://tex.z-dn.net/?f=t%5E2-2t-8%3D0)
Factor that and find t values of 4 and -2. Again, we know that time will never be negative, so
t = 4 seconds.
This strategy works because if you subtract one number from another the sum of the two numbers should be the that is being subtracted from. (In this case, it's 200)
Answer:
The slope (m) = 1/3 and the y-intercept (b) = -4
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