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3 years ago

PLEASE I NEED IT NOW!

Mathematics

2 answers:

charle [14.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

multiplying by 2 gives C=4*pi*r

make r = 3 for example, and you get C = 6pi

when you plug r into the new formula, C= 12pi, which is double

tresset_1 [31]3 years ago

4 0

Answer:

Step-by-step explanation:

hope this helps! have a wondefull day! :)

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If we changed the 2 to a 5 in the domain restriction x < 2 what would happen to the graph?

grigory [225]

Answer:

what would happen is that the dotted line that is at 2 and down right now would go up to 5

Hope This Helps!!!

7 0

2 years ago

Make p the subject of this formulae q-2p=p+4

daser333 [38]

Answer:

f(p)=3p+4

Explanation:

6 0

3 years ago

4x+(7-3)5=10 please help with this one

Ostrovityanka [42]

Answer:

x=-2.5

Step-by-step explanation:

4x+(7-3)5=10

4x+(4)5=10

4x+20=10

subtract 20 from each side

4x=-10

divide each side by 4

x=-2.5

3 0

3 years ago

Read 2 more answers

3.5 hours: $10 or 1/2 hour: $1.25 which is the better deal

mina [271]

A) 1.42
B) 1.25
Second choice

8 0

3 years ago

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

3 0

3 years ago