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netineya [11]
3 years ago
12

Help please Find the zeros for y=(x-2)(x+7)

Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

x = 2 and x = -7

Step-by-step explanation:

To find y = 0, so you need either x - 2 =0 or x + 7 =0, so x can be 2 or -7.

If it is helpful, plz give me Brainliest.

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Review the graph. What is the component form and direction of the vector shown
Charra [1.4K]

Answer:

<-7,3> and 157 degrees

got it right :) hope this helped

4 0
3 years ago
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Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
A count went from 605 to 203. What was the approximate percent decrease? Round the numbers to find an estimate of the percent de
topjm [15]

Answer:

66%

Step-by-step explanation:

5 0
3 years ago
Help meh plsssss!!!!
Mashutka [201]

4

you were right because -15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 so that's 19 numbers

8 0
3 years ago
Find the volume on the following prims it says please help me!! I need to find the volume :)
Delvig [45]

Answer:

V = 277.088 m³

Step-by-step explanation:

Volume of Cylinder Formula: V = πr²h

We are given <em>r</em> = 4.2 and <em>h</em> = 5, so simply plug it into the formula and solve:

V = π(4.2)²(5)

V = 17.64π(5)

V = 88.2π

V = 277.088

7 0
3 years ago
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