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3 years ago

Parallel lines and tranvsveral

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Answer:

66°

Step-by-step explanation:

simply subtract 114 from 180

you'll come out with the answer of 66°.

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Question 1

fredd [130]

Hello!

The graphs of sine and cosine are waves. Therefore, choice A and B are wrong.

The graph of f(x) = cot(x) is an inverse of f(x) = tan(x), so therefore the graph of f(x) = cot(x) has the lines similar to the graph above, but it's flipped.

So therefore, the graph shown above is choice C, f(x) = tan x.

8 0

3 years ago

The product of 1540 and m is a square number. find the smallest possible value of m

aliina [53]

The smallest possible value of m according to the task is; 1/1540.

<h3>What is the smallest possible value of m?</h3>

Since it follows from the task content that the product of 1540 and m is a square number and the smallest possible small number is; 1.

The equation which holds true is; 1540 × m = 1

Consequently, m = 1/1540.

Read more on square numbers;

brainly.com/question/123907

#SPJ1

5 0

2 years ago

C=1/21.22.23+1/22.23.24+................+1/200.201.202 . = là dấu nhân

Aneli [31]

It looks like you have to find the value of the sum,

$C = \displaystyle \frac1{21\times22\times23} + \frac1{22\times23\times24} + \cdots + \frac1{200\times201\times202}$

so that the n-th term in the sum is

$\dfrac1{(21+(n-1))\times(21+n)\times(21+(n+1))} = \dfrac1{(n+20)(n+21)(n+22)}$

for 1 ≤ n ≤ 180.

We can then write the sum as

$\displaystyle C = \sum_{n=1}^{180} \frac1{(n+20)(n+21)(n+22)}$

Break up the summand into partial fractions:

$\dfrac1{(n+20)(n+21)(n+22)} = \dfrac a{n+20} + \dfrac b{n+21} + \dfrac c{n+22}$

Combine the fractions into one with a common denominator and set the numerators equal to one another:

$1 = a(n+21)(n+22) + b(n+20)(n+22) + c(n+20)(n+21)$

Expand the right side and collect terms with the same power of n :

$1 = a(n^2+43n+462)+b(n^2+42n+440) + c(n^2+41n + 420) \\\\ 1 = (a+b+c)n^2 + (43a+42b+41c)n + 462a+440b+420c$

Then

a + b + c = 0

43a + 42b + 41c = 0

462a + 440b + 420c = 1

==> a = 1/2, b = -1, c = 1/2

Now our sum is

$\displaystyle C = \sum_{n=1}^{180} \left(\frac1{2(n+20)}-\frac1{n+21}+\frac1{2(n+22)}\right)$

which is a telescoping sum. If we write out the first and last few terms, we have

C = 1/(2×21) - 1/22 + 1/(2×23)

… … + 1/(2×22) - 1/23 + 1/(2×24)

… … + 1/(2×23) - 1/24 + 1/(2×25)

… … + 1/(2×24) - 1/25 + 1/(2×26)

… … + … - … + …

… … + 1/(2×198) - 1/199 + 1/(2×200)

… … + 1/(2×199) - 1/200 + 1/(2×201)

… … + 1/(2×200) - 1/201 + 1/(2×202)

Notice the diagonal pattern of underlined and bolded terms that add up to zero (e.g. 1/(2×23) - 1/23 + 1/(2×23) = 1/23 - 1/23 = 0). So, like a telescope, the sum collapses down to a simple sum of just six terms,

C = 1/(2×21) - 1/22 + 1/(2×22) + 1/(2×201) - 1/201 + 1/(2×202)

which we simplify further to

C = 1/42 - 1/44 - 1/402 + 1/404

C = 1,115/1,042,118 ≈ 0.00106994

4 0

3 years ago

X^2-x-42 what is the fractored forms

igomit [66]

The factored forms of that is (x + 6) (x - 7).

If you have any questions then please leave a comment. Good luck!

5 0

3 years ago

6. The price of a necklace is four times that of a

Lunna [17]

Answer:

The necklace is 4x.

Step-by-step explanation:

If the bracelet is x and the necklace is 4 times greater you would multiply the cost of the bracelet by 4. Meaning it would be X *4= 4x (x multiplied 4 times.)

3 0

3 years ago