All categories

3 years ago

What is the solution to the equation?

Mathematics

2 answers:

andrezito [222]3 years ago

7 0

Answer:

(D). 6

Step-by-step explanation:

$\sqrt{x-2}$ + 4 = x and x ≥ 2

Let analyze the answer's choices

(A). Does not satisfy domain

(B). $\sqrt{3-2}$ + 4 ≠ 3

(C). Does not satisfy domain

(D). √(6 - 2) + 4 = 6 ⇒ x = 6 is the answer.

KonstantinChe [14]3 years ago

4 0

Answer: D
1/2x-1+4=x
1/2x-x=-3
-1/2x=-3
x=6

You might be interested in

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

4 years ago

Read 2 more answers

Pls help asapppppppp

denis23 [38]

Answer:

Step-by-step explanation:

5 0

2 years ago

Factor the following Polynomials 9x^2 - 42x + 49

Allisa [31]

Answer:(3x-7) (3x-7)

Step-by-step explanation:

9x2-42x+49

The two by the 9 is power of 2 so the small two above

6 0

3 years ago

What's the perimeter of a rectangular hexagon with one side measures 3 inches

MakcuM [25]

Answer:

6 sides of the hexagon * one side length of 3 inches = 18

Step-by-step explanation:

3 0

3 years ago

(-10)³ * 3 * 2 * (-7 ) Please help

viktelen [127]

Answer:

i think it is 42000 but i could be wrong

Step-by-step explanation:

8 0

2 years ago