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dsp73
3 years ago
12

A country has 23,456,900 citizens out of those 5.5 million are under 5.5 feet tall. What percentage of the population is under 5

.5 feet tall?
Mathematics
1 answer:
shusha [124]3 years ago
5 0
To get the percentage of citizens under 5ft total we use the formula:
(number of citizens who are under 5.5 ft)/(Total population)×100%
number of citizens who are under 5.5 ft=5,500,000
Total population=23,456,900
Hence:
Percentage of population under 5.5 ft tall
=5,500,000/23,456,900×100
=23.45%

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Which of the following is the reciprocal of x2 – 2x – 8?
Ann [662]
Hi again

x² - 2x - 8
Factor
= (x + 2)(x -4)
Answer : A is the correct option.


If you wanna check if A is the right answer, I will solve it for you and it will you give you the exact answer which will be x² - 2x - 8
(x+2)(x-4)
Distribute
(x)(x) + (x)(-4)+(2)(x)+(2)(-4)
= x² - 4x + 2x - 8
= x² - 2x - 8
Here it is, we find the exam answer.

Thus, (x+2)(x-4) is the reciprocal of x² -2x - 8


I hope that's help !
6 0
3 years ago
Find the value of a and b in x^2+2x=13
zheka24 [161]

Answer:

a =1  and b =2

Step-by-step explanation:

The standard quadratic is written in the form

ax^2 +bx+c =0

x^2 +2x -13 =0

a =1  and b =2

8 0
3 years ago
A prism is completely filled with 80 cubes that have edge length of 12cm What is the volume of the prism?
krek1111 [17]
<h3>Answer:  138,240 cubic cm</h3>

Explanation:

If x is the side length of a cube, then x^3 is the volume. Think of it like length*width*height, but length = width = height.

It's no coincidence that the cubing operation or cubed exponent ties directly to the concept of things like volumes in cubic cm.

In this case, x = 12 cm is the side length of each small cube. The volume of each small cube is x^3 = 12^3 = 12*12*12 = 1728 cubic cm.

Eighty such small cubes get us a total volume of 80*1728 = 138,240 cubic cm.

4 0
2 years ago
PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi
Irina18 [472]

Answer:

Question 1: P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}

Question 2:

A. P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

B. P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

C. P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

Step-by-step explanation:

Conditional probability is defined by

P(A|B)= \frac{P(A and B)}{P(B)}

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} }  = \frac{1}{2}

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

then

P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

so

P((YorZ) and B)= \frac{3}{16}

By definition,

P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

3 0
3 years ago
The output is eleven more than the input
Y_Kistochka [10]
X is the input and y is the output, "more" indicates addition, so 11 more than the input equals x + 11. Answer: y = x + 11
8 0
3 years ago
Read 2 more answers
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