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kirza4 [7]
2 years ago
15

Use any of the digits 1, 3, and 9 and the operation signs +, -, x, divide, to write all the whole numbers from 1 through 13. Eac

h digit can be expressed only once in each example. You can use other digits in the expression, but you must also use a 1, 3, or 9 at least once in each expression.

Mathematics
2 answers:
Nikolay [14]2 years ago
7 0

Answer:

d) 3+1

e) 9-3-1

f) 9-3

g) 9-3+1

h) 9-1

i) 9 x 1

j) 9+1

k) 9+3-1

l) 9+3

m) 9+1+3

Kryger [21]2 years ago
6 0
3+1 or 9-5
4x1 or 5-1
15/3 or 4+1
54/9 or 7-1
7x1 or 7-0
64/8 or 11-3
9x1 or 81/9
19-9 or 7+3
21-10 or 11x1
9+3 or 12/1
14-1 or 13x1

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The correct answer is 720. Just turned it in and got a 100. Good luck and hoped this help ya.
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X + 8 = 9. Find the value of x.
algol [13]

Answer:

x = 1

Step-by-step explanation:

x + 8 = 9

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=> x = 1

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Two fifths of one less than a number is less than three fifths of one more than that number .what numbers are in the solution se
Lelechka [254]

2/5(x - 1) < 3/5(1 + x)

To find the solution, we can use the distributive property to simplify.

2/5x - 2/5 < 3/5 + 3/5x

Multiply all terms by 5.

2x - 2 < 3 + 3x

Subtract 2x from both sides.

-2 < 3 + x

Subtract 3 from both sides.

-5 < x

<h3><u>The value of x is greater than the value of -5.</u></h3>
5 0
2 years ago
Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.
Kobotan [32]

Answer:

t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457

p_v =P(t_{75}  

Comparing the p value with a significance level for example \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.  

Step-by-step explanation:

Data given and notation

\bar X_{A}=3.7 represent the mean for athletes  

\bar X_{NA}=4.1 represent the mean for non athletes  

s_{A}=1.1 represent the sample standard deviation for athletes  

s_{NA}=1.3 represent the sample standard deviation for non athletes

n_{A}=32 sample size for the group 2  

n_{NA}=45 sample size for the group 2  

\alpha=0.01 Significance level provided  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of  hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{NA}\geq 0  

Alternative hypothesis:\mu_{A} - \mu_{NA}< 0  

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}} (1)  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457

P value  

We need to find first the degrees of freedom given by:

df=n_A +n_{NA}-2=32+45-2=75

Since is a one left tailed test the p value would be:  

p_v =P(t_{75}  

Comparing the p value with a significance level for example \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.  

5 0
3 years ago
Jason takes 2 cL of medicine. How many ml is this
AVprozaik [17]
One centiliter is equal to ten milliliters  so Jason is taking 20 ml of medicine, You multiply 2cl X 10ml = 20ml 
7 0
3 years ago
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