Answer:
395, 17.212
(360.576,429.424)
Step-by-step explanation:
Given that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.
Here
Since np and nq are greater than 5 by rule of thumb we can approximate binomial to normal.
Mean = np = 395
Variance = npq =
Std dev = 17.212
Thus X no of successes is N(395, 17.212)
THe the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma would be
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
(0, 1, 0)
The vector equation is given as:
Substitute values for x, y and z
Differentiate:
The parametric value that corresponds to (0, 1, 0) is:
Substitute 0 for t in r'(t)
The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)
It should be noted that:
The equation of a line through position vector a and parallel to vector v is given as:
Such that:
and
The equation becomes:
By comparison:
and
The parametric equations for the tangent line are:
