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tigry1 [53]
4 years ago
13

Find the area of the shape shown below.

Mathematics
2 answers:
maw [93]4 years ago
8 0

Answer:

The area is 28.

Step-by-step explanation:

Visualize the rectangle as 2 split squares.

The top square is easily 4x4, so the area of that part is 16.

Now visualize the bottom square as two rectangles.

To find the area of the dented side, you would use the equation of finding the area of a triangle, a=(w x h)\frac{1}{2} because the dented side is actually just one half of the rectangle on the other side.

Since it is the same height as the top square, but is 2 in width, it would be written as a=(2 x 4)\frac{1}{2} . So the area of that part is 4, and the area of the other rectangle would be just 2 x 4 so it is 8.

Totaling these numbers, you get the area of the full rectangle.

kakasveta [241]4 years ago
6 0

Answer:

28

Step-by-step explanation:

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2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo
Likurg_2 [28]

Answer:

The given equation is

25x^{2} +4y^{2}=100

Which represents an elipse.

To find its elements, we need to divide the equation by 100

\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1

Where a^{2} =25 and b^{2}=4. Remember that the greatest denominator is a, and the least is b. So, we extract the square root on each equation.

a=5 and b=2.

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is 2a=2(5)=10.

The length of the minor axis is 2b=2(2)=4.

The vertices are (0,5);(0,-5) and (2,0);(-2,0).

Now, the main parameters of an elipse are related by

a^{2}=b^{2} +c^{2}, which we are gonna use to find c, the parameter of the focus.

c=\sqrt{a^{2}-b^{2} }=\sqrt{25-4}=\sqrt{21}

So, the coordinates of each focus are (0,\sqrt{21}) and (0,-\sqrt{21})

The eccentricity of a elipse is defined

e=\frac{c}{a}=\frac{\sqrt{21} }{5}  \approx 0.92

The latus rectum is defined

L=\frac{2b^{2} }{a}=\frac{2(4)}{5} =\frac{8}{5} \approx 1.6

Finally, the graph of the elipse is attached.

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A car purchased for $15,000 depreciates under a straight-line method in the amount of $950 each year. Which equation below best
alexandr1967 [171]
I believe it will be B. y = 15,000 - 950 x
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