Question

A manufacturer earns Rs4500 in the first month and Rs 6000 in second month. On plotting these points a manufacturer observes a linear function. Find the linear function that fits in data?

Answer 1

Answer:

$f(x) = 1500x +3000$

Step-by-step explanation:

Given

Represent the months with x and the earnings with y.

So:

$(x_1,y_1) = (1,4500)$

$(x_2,y_2) = (2,6000)$

Required

Determine the linear function

First, calculate slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{6000 - 4500}{2 - 1}$

$m = \frac{1500}{1}$

$m = 1500$

The equation is then calculated using:

$y = m(x - x_1) + y_1$

$y = 1500(x - 1) + 4500$

$y = 1500x - 1500 + 4500$

$y = 1500x +3000$

As a function, we have:

$f(x) = 1500x +3000$