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malfutka [58]
3 years ago
12

Find two consecutive integers such that the larger is nine more than twice the smaller

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0
If x is one integer and x+1 is the next, we have 2*x+9=x+1. Subtracting 9 and x from both sides, we get x(the smaller number)=-8 and the larger number is -7. 
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(-5, -11) and (-2, 1)
irinina [24]

Answer:

the answer is 0 because it 3 negative number

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Simplify. (2/5)^4... words to fill in minimum space
Stella [2.4K]
When you have a power to a fraction, you simply take it by the top and then by the bottm.

So, split it into two: (2)^4 and (5)^4

Solve: (2)^4=16
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So the fraction is: 16/625

Check to see if it reduces: It doesn't. (Odd and even numbers that have no common multiples).

Therefore, that's the answer.
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Please help me! What is x and y? Thank you!
Ivahew [28]

Answer:

x=3. y=6

Step-by-step explanation:

So, to solve x and y, we need to take the equivelent sides of the two triangles, take their equations, and solve them.

So to find what x equals, we can take the 13, and make it equal to the 4x+1:

13=4x+1

Subtract the one from both sides:

12=4x

Divide both sides by 4:

3=x

Or

<u>x=3</u>

So we know the x value is 3.

Now lets solve for y using the bottom equations:

2x+y=8x-2y

Subtract 1y from both sides:

2x=8x-3y

Subtract 8x from both sides:

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Divide both sides by -6:

x=1/2y

So we already know that x=3, lets plug that in for x, and solve for y:

3=1/2y

Or

1/2y=3

Multiply both sides by 2 to get 1y:

<u>y=6</u>

So we know that y is equal to 6.

Hope this helps!

7 0
3 years ago
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