The correct answer to this problem is
C=3
Y=3
You add 8 and 5 so the equation would be 8+5=13
A is located, as you look A is past -2 almost hitting -3 making the mark 2.8 so the answer is A
5:3
5 to 3
5/3
Is that what you are looking for?
The blanks can be filed by exactly, domain, range, and, f(x) respectively.
While we've got a feature in formulation form, it also includes a simple count to assess the function. For example, the feature f(x)=5−3x2 f ( x ) = 5 − 3 x 2 can be evaluated with the aid of squaring the enter cost, multiplying by means of three, and then subtracting the product from 5.
You write capabilities with the function name observed by way of the established variable, together with f(x), g(x), or maybe h(t) if the function depends upon time. You read the function f(x) as "f of x" and h(t) as "h of t". functions no longer need to be linear. The feature g(x) = -x^2 -3x + 5 is a nonlinear characteristic.
A user is an actual-valued feature on a vector area, usually of functions. as an example, the electricity practical at the unit disk assigns various to any differentiable feature, For the practical to be non-stop, it's miles necessary for the vector space. of capabilities to have the perfect topology.
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