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Lerok [7]
3 years ago
10

Find the tangent line to the graph of f(x)=x at point (0,0)

Mathematics
1 answer:
ratelena [41]3 years ago
4 0

Given:

The function is

f(x)=x

To find:

The tangent line to the graph of f(x)=x at point (0,0).

Solution:

We have,

f(x)=x

It is a linear function because the highest power of the variable is 1.

We know that the tangent line to a linear function at any point is the line itself.

Derivative of given function is

f'(x)=1

So, slope of the tangent line is 1. It is given table the tangent line passes through the point (0,0). The equation of tangent line is

y-0=1(x-0)

y=x

Therefore, the tangent line to the graph of f(x)=x at point (0,0) is y=x.

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Jaymie wants to construct congruent angles with a compass and straightedge, while Annie wants to construct congruent segments wi
SashulF [63]

Jaymie will measure the segment and then place the point just across from the line's beginning point to create a congruent segment that shows the similarity between them.

<h3>What are the conditions of the congruent triangle?</h3>

Triangles that are equivalent in terms of size and form are known as a congruent triangle.

Segments will be built using the straightedge, and measurements will be taken using the compass. They will pick a starting point and draw a line using the straightedge, then use the compass to finish the job.

To make the congruent segment, Jaymie will measure the segment and then position the point that is opposite from the line's starting point.

Jaymie, on the other hand, will have to work a bit harder with the compass since she will need to draw a semi-circle in the original angle and transfer this measurement to the new line in order to create congruent angles.

To learn more about the congruent triangle refer;

brainly.com/question/12413243

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6 0
2 years ago
What shape is this ​
suter [353]

Step-by-step explanation:

blank I don't see a shape

4 0
3 years ago
PLEASE HELP IM ON A TIME LIMIT :(
Mice21 [21]

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

\sqrt{ {1}^{2} +  {1}^{2}  }

=  \sqrt{2}

DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

7 0
3 years ago
Write a slope-intercept equation of a line that passes through (-3,4) and (3,-8)
Umnica [9.8K]
Y=-2x-2 is the right answer
4 0
3 years ago
What is<br> |-3+45-(-14)|+(-|-87+12/46|<br> simplified
USPshnik [31]
|x|=absoulte value of x  which means whatever x is, make it positive
so first solve any division/multiplication

the only one is 12/46=6/23
so we do the absoulte value signs
-3+45-(-14)
-(-14)=+14
-3+45+14=56
absoulute value of 56=56

56+(-|-87+6/23|)
-87+6/23=-86 and 17/23
absoulte value of -86 and 17/23=86 and 17/23
there is a negative sign in front of the absoulte vaulue so make it negative
56-86 and 17/23=-30 and 17/23 or about -30.73913
4 0
3 years ago
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