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3 years ago

Find the tangent line to the graph of f(x)=x at point (0,0)

Mathematics

1 answer:

ratelena [41]3 years ago

4 0

Given:

The function is

$f(x)=x$

To find:

The tangent line to the graph of f(x)=x at point (0,0).

Solution:

We have,

$f(x)=x$

It is a linear function because the highest power of the variable is 1.

We know that the tangent line to a linear function at any point is the line itself.

Derivative of given function is

$f'(x)=1$

So, slope of the tangent line is 1. It is given table the tangent line passes through the point (0,0). The equation of tangent line is

$y-0=1(x-0)$

$y=x$

Therefore, the tangent line to the graph of f(x)=x at point (0,0) is y=x.

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KonstantinChe [14]

Answer:

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Step-by-step explanation:

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3 years ago

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How do you do this problem

Fudgin [204]

A triangle is 180°; therefore:
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3 years ago

how many liters of glycerin should be added to 12 Liters of an 8% glycerin solution so that the resulting solution contains 16%

mojhsa [17]

Answer:

1.14 liters

Step-by-step explanation:

We have 8% glycerin solution and we need to make it 16% glycerin solution [more concentration].

When we add "x" liters, we add glycerin as well as changes the total. in 12 Liters, there is 12 * 0.08 = 0.96Liters of glycerin. How much we need to add to this??

Note, 16% = 0.16

We can write a Ratio as shown below, cross multiply and solve for x:

$\frac{0.96+x}{12+x}=0.16\\(12+x)(0.16)=0.96+x\\1.92+0.16x=0.96+x\\1.92-0.96=x-0.16x\\0.96=0.84x\\x=1.14$

We need to add around 1.14 liters

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3 years ago

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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t

katrin2010 [14]

Answer:

$\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24$

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of $\triangle ACD$ and the hypotenuse of $\triangle ADB$ .

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}$

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is $\angle CAD$ . The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

$\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}$

Now use this value in the Law of Sines to find AD:

$\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}$

Recall that $\sin 45^{\circ}=\frac{\sqrt{2}}{2}$ and $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ :

$AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}$

Now that we have the length of AD, we can find the length of AB. The right triangle $\triangle ADB$ is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio $x:x\sqrt{3}:2x$ , where $x$ is the side opposite to the 30 degree angle and $2x$ is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent $2x$ in this ratio and since AB is the side opposite to the 30 degree angle, it must represent $x$ in this ratio (Derive from basic trig for a right triangle and $\sin 30^{\circ}=\frac{1}{2}$ ).